Python 错误“<method> 缺少 1 个必需的位置参数：'self'”

Question

Python 的新手。尝试创建一个简单的示例来演示 2 个级别的抽象。收到错误 TypeError: 'HPNotebook' object is not callable "

我查看了大量示例，但仍然感到困惑。

为了理解，我在代码中展示了 3 个级别。
你能指点我帮助解释这个问题以及如何消除它的地方吗？提供有关如何纠正此问题的建议。谢谢

from abc import abstractmethod,ABC   #this is to allow abstraction. the ABC forces inherited classes to implement the abstracted methods.

class TouchScreenLaptop(ABC):
    def __init__(self):
        pass
    @abstractmethod      #indicates the following method is an abstract method.
    def scroll(self):    # a function within the parent
        pass             #specifically indicates this is not being defined
    @abstractmethod      #indicates the following method is an abstract method.
    def click(self):    
        pass             #specifically indicates this is not being defined

class HP(TouchScreenLaptop):
    def __init__(self):
        pass
    @abstractmethod         #indicates the following method is an abstract method.
    def click(self):    
        pass  
    def scroll(self):
        print("HP Scroll")

class HPNotebook(HP):
    def __init__(self):
        self()
    def click(self):
        print("HP Click")    
    def scroll(self):
        HP.scroll()

hp1=HPNotebook()
hp1.click()                  #the 2 level deep inherited function called by this instance
hp1.scroll()                 #the 1 level deep inherited function called by this instance

Answer 1

只需将 HPNotebook.__init__ 上的 self() 替换为 super()，将 HPNotebook.scroll 上的 HP.scroll() 替换为 super().scroll()。

class HPNotebook(HP):
    def __init__(self):
        super()
    def click(self):
        print("HP Click")    
    def scroll(self):
        super().scroll()

此外，检查 this link 以更好地理解 python 继承。

Python 错误“<method> 缺少 1 个必需的位置参数：'self'”

Python Error " <method> missing 1 required positional argument: 'self' "

python

abstraction