JdbcTemplate 查询 returns BadSqlGrammarException

Question

Postgres 数据库：

CREATE TYPE pr_status_name AS ENUM ('CREATED', 'SUCCESS', 'FAILED');

create table payment_request_statuses(
    status_id serial PRIMARY KEY,
    pr_status_name pr_status_name NOT NULL
);

INSERT INTO payment_request_statuses(pr_status_name) VALUES ('CREATED');
INSERT INTO payment_request_statuses(pr_status_name) VALUES ('SUCCESS');
INSERT INTO payment_request_statuses(pr_status_name) VALUES ('FAILED');

当我尝试执行方法时：

        Map<String, Object> data = jdbcTemplate.queryForMap("select * from payment_request_statuses where pr_status_name = ?", new Object[]{"CREATED"});

我收到以下错误：

rg.springframework.jdbc.BadSqlGrammarException: PreparedStatementCallback; bad SQL grammar [select * from payment_request_statuses where pr_status_name = ?]; nested exception is org.postgresql.util.PSQLException: ERROR: operator does not exist: pr_status_name = character varying
  Hint: No operator matches the given name and argument types. You might need to add explicit type casts.

似乎，由于某种原因，jdbcTemplate 无法 transform/match 字符串到 db 枚举对象，这让我感到惊讶。

我该如何解决？

Answer 1

您需要在 SQL 中将字符串转换为枚举。

Map<String, Object> data = jdbcTemplate.queryForMap("select * from payment_request_statuses where pr_status_name = ?::pr_status_name", new Object[]{"CREATED"});

JdbcTemplate 查询 returns BadSqlGrammarException

JdbcTemplate query returns BadSqlGrammarException

postgresql

spring-jdbc

jdbctemplate