如何检查给定时间是否在上述时间范围内

Question

我想检查我的日期值是否来自 -

Date d = convertCurrentTimeToSpecificTimeZone("America/Chicago", 2, 30);

上午 10 点到下午 6 点之间。

我在 Whosebug similar question 上找到了一些类似的链接，并使用了该线程中的一些代码。

我只想检查任何时区的当前时间是否在上午 10 点到下午 6 点的范围内。如果是，打印 "yes" 否则打印 "no".

当前用于以下代码：

    String string1 = "10:11:13";
    Date time1 = new SimpleDateFormat("HH:mm:ss").parse(string1);
    Calendar calendar1 = Calendar.getInstance();
    calendar1.setTime(time1);
    calendar1.add(Calendar.DATE, 1);
    System.out.println(calendar1.getTime().toString());

它只打印 1970 年的 10:11 上午时间。像这样 - 1 月 2 日星期五 10:11:13 IST 1970.

但我想检查今天或任何未来的日期时间是否在上午 10 点到下午 6 点的范围内。

下面是代码参考：

public static Date convertCurrentTimeToSpecificTimeZone(String timeZone, int increaseDateBy,
        int increaseMinutesBy) {
    Calendar calendar = Calendar.getInstance();
    TimeZone fromTimeZone = calendar.getTimeZone();
    TimeZone toTimeZone = TimeZone.getTimeZone(timeZone);
    calendar.setTimeZone(fromTimeZone);
    calendar.add(Calendar.MILLISECOND, fromTimeZone.getRawOffset() * -1);
    if (fromTimeZone.inDaylightTime(calendar.getTime())) {
        calendar.add(Calendar.MILLISECOND, calendar.getTimeZone().getDSTSavings() * -1);
    }
    calendar.add(Calendar.MILLISECOND, toTimeZone.getRawOffset());
    if (toTimeZone.inDaylightTime(calendar.getTime())) {
        calendar.add(Calendar.MILLISECOND, toTimeZone.getDSTSavings());
    }
    increaseCalenderDateBy(calendar, increaseDateBy);
    increaseCalenderMinuteBy(calendar, increaseMinutesBy);
    return calendar.getTime();
}

public static void getTimeBetweenRange() throws ParseException {
    String string1 = "10:11:13";
    Date time1 = new SimpleDateFormat("HH:mm:ss").parse(string1);
    Calendar calendar1 = Calendar.getInstance();
    calendar1.setTime(time1);
    calendar1.add(Calendar.DATE, 1);
    System.out.println(calendar1.getTime().toString());

    String string2 = "18:49:00";
    Date time2 = new SimpleDateFormat("HH:mm:ss").parse(string2);
    Calendar calendar2 = Calendar.getInstance();
    calendar2.setTime(time2);
    calendar2.add(Calendar.DATE, 1);
    System.out.println(calendar2.getTime().toString());

    Date d = convertCurrentTimeToSpecificTimeZone("America/Chicago", 2, 30);
    Calendar calendar3 = Calendar.getInstance();
    calendar3.setTime(d);
    System.out.println(calendar3.getTime().toString());

    Date x = calendar3.getTime();
    if (x.after(calendar1.getTime()) && x.before(calendar2.getTime())) {
        // checkes whether the current time is between 14:49:00 and 20:11:13.
        System.out.println(true);
    } else
        System.out.println(false);
}

所以我下面代码的输出是：

Fri Jan 02 10:11:13 IST 1970
Fri Jan 02 18:49:00 IST 1970
Fri Jan 31 03:15:07 IST 2020

Answer 1

All I want to check if the current time from any timezone falls under the range of 10 am to 6 pm. If Yes, print "yes" else print "no".

为此，以下代码将完成这项工作。

LocalTime lt = LocalTime.now();
if( lt.isAfter( LocalTime.of( 10, 0 ) ) && lt.isBefore( LocalTime.of( 18, 0 ) ) ) System.out.println( "Yes" );
else System.out.println( "No" );

由于您有 Date 个实例，您可以将它们转换为 LocalTime 个实例，如下所示，并使用相同的比较机制。

Date d = new Date(); //Change this to your way of creating the Date instance
LocalTime lt = LocalDateTime.ofEpochSecond( d.getTime(), 0, ZoneOffset.ofHours( 0 ) ).toLocalTime();

希望对您有所帮助。

Answer 2

一个简单的方法可能是将您的时间 String 解析为 LocalTime 的实例并进行比较。您必须决定开始和结束时间是否包含...

支持某些格式，因为您可能必须通过 AM/PM 或不带 String 的格式：

public static boolean isInTimeSlot(String time, String timeSlotStart, String timeSlotEnd) {
    // create a formatter that supports different formats for the String arguments
    DateTimeFormatter parserDtf = DateTimeFormatter.ofPattern("[hh:mm:ss a][HH:mm:ss][h a]");
    // parse each argument to a LocalTime
    LocalTime timeOfDay = LocalTime.parse(time, parserDtf);
    LocalTime fromTime = LocalTime.parse(timeSlotStart, parserDtf);
    LocalTime toTime = LocalTime.parse(timeSlotEnd, parserDtf);
    // and return if the given time is in the time slot (including start and end time)
    return timeOfDay.equals(fromTime) || timeOfDay.equals(toTime)
            || (timeOfDay.isAfter(fromTime) && timeOfDay.isBefore(toTime));
}

如果你运行像这样main它

public static void main(String[] args) {
    // provide some sample times
    String[] times = { "10:31:17", "09:59:59", "6 PM", "4 AM", "06:00:01 PM" };
    // provide a time slot
    String from = "10 AM";
    String to = "6 PM";

    // check the method for each time string
    for (String time : times) {
        if (isInTimeSlot(time, from, to)) {
            System.out.println(time + " is in the time slot at or between "
                                + from + " and " + to);
        } else {
            System.err.println(time + " is not in the time slot at or between " 
                                + from + " and " + to);
        }
    }
}

输出将是

10:31:17 is in the time slot at or between 10 AM and 6 PM
09:59:59 is not in the time slot at or between 10 AM and 6 PM
6 PM is in the time slot at or between 10 AM and 6 PM
4 AM is not in the time slot at or between 10 AM and 6 PM
06:00:01 PM is not in the time slot at or between 10 AM and 6 PM

Answer 3

不是很清楚。对于这个答案，我假设您的所有时间都在 America/Chicago 时区内理解。如果这不是您想要的，请恢复。

java.time

    ZoneId zone = ZoneId.of("America/Chicago");

    ZonedDateTime zdt = ZonedDateTime.now(zone).plusDays(2).plusMinutes(30);

    LocalTime rangeStart = LocalTime.parse("10:11:13");
    LocalTime rangeEnd = LocalTime.parse("18:49:00");

    LocalTime time = zdt.toLocalTime();
    if (!time.isBefore(rangeStart) && time.isBefore(rangeEnd)) {
        System.out.println("Yes");
    } else {
        System.out.println("No");
    }

当我运行刚才的代码片段（在 11:30 芝加哥时间）时，输出是：

Yes

我正在使用 java.time，现代 Java 日期和时间 API，建议您也这样做。与旧的、过时的和设计不佳的类 Date、SimpleDateFormat、Calendar 和 TimeZone.

相比，它更好用。

A LocalTime 是一天中从 00:00（含）到 24:00（不含）的时间。通过比较 LocalTime 对象，我们忽略了日期并且在 1970 年或历史上的其他时间不相关的日期没有问题。

编辑：

Also is it possible to get the date and time of rangeStart and rangeEnd in order to verify for which particular day and time we are checking the conditions?

不，那没有意义。由于 LocalTime 是一天中的时间 没有日期 ，因此无法从中获取日期。但是您可以打印 ZonedDateTime 并验证其日期部分。并确保您自己的代码是正确的，编写一些单元测试。

Link: Oracle tutorial: Date Time 解释如何使用 java.time.

如何检查给定时间是否在上述时间范围内

How to check if the given time falls in mentioned time range

java

time

calendar

date

range

java.time