Hive

Question

如何获取分配给 "USA_RBB_WA_BU" 的仅“_WA”数据的数据？但是，我查看的列中有包含 _WA 和 _SA (USA_CA_SAWANT)

的行

我用过，

                        select....
                         'USA_RBB_WA_BU' AS State ,
                         District 
                         from TABLE where district like '%_WA%'


                        select   ...
                         'USA_RBB_NSW_BU' AS State ,
                         District 
                         from TABLE where district like '%_SA%'

但是我最终的数据输出table低于

**state                  district**
USA_RBB_NSW_BU          USA_CA_SAWANT
USA_RBB_WA_BU           USA_CA_SAWANT
USA_RBB_NSW_BU          USA_CA_SAWANT
USA_RBB_WA_BU           USA_CA_SAWANT

我试过了

                        select....
                         'USA_RBB_WA_BU' AS State ,
                         District 
                         from TABLE where district like '_WA%'

                         output was  was 0 results in hive

Answer 1

我猜你是想在这里转义_。试试下面 -

SELECT <FIELD_LIST>
       'USA_RBB_WA_BU' AS State ,
       District 
FROM TABLE
WHERE district RLIKE '.*_WA%'

Answer 2

where district rlike '_WA' 将正常工作（如果字符串包含 _WA，这将 return 为真）

如果你希望字符串在_WA之前和之后包含一些东西，添加.+（任意字符一次或多次）：

where district rlike '.+_WA.+'

Hive - 在 string/row 中的任意位置找到 2 个字符 - RLIKE

Hive - find 2 characters anywhere in the string/row - RLIKE

sql

hiveql

sql-like

regexp-like