Maven

Question

假设我有 3 个包，需要为每个只包含当前包中内容的包创建一个 jar。我的尝试是：

<plugin>
                <groupId>org.apache.maven.plugins</groupId>
                <artifactId>maven-jar-plugin</artifactId>
                <version>2.4</version>
                <executions>
                    <execution>
                        <id>first-jar</id>
                        <goals>
                            <goal>jar</goal>
                        </goals>
                        <configuration>
                            <classifier>first-jar</classifier>
                            <excludes>
                                <exclude>/maven.task.3/src/main/java/third/ThirdMain.java
                                </exclude>
                                <exclude>/maven.task.3/src/main/java/second/SecondMain.java
                                </exclude>
                            </excludes>
                        </configuration>
                    </execution>
                    <execution>
                        <id>second-jar</id>
                        <goals>
                            <goal>jar</goal>
                        </goals>
                        <configuration>
                            <classifier>second-jar</classifier>
                            <excludes>
                                <exclude>/maven.task.3/src/main/java/first/FirstMain.java
                                </exclude>
                                <exclude>/maven.task.3/src/main/java/third/ThirdMain.java
                                </exclude>
                            </excludes>
                        </configuration>
                    </execution>
                </executions>
            </plugin>

这确实创建了不同的 jar，但是里面的内容是相同的，这意味着排除条款不起作用。我尝试只排除 class(relative/absolute 路径) 和包。不要问我为什么这样做是为了家庭作业，这没有多大意义！这是我尝试做的方法，如果还有其他更有效的方法，请随时与我分享！

编辑：不得使用模块化结构，它必须是一个项目。

提前致谢

Answer 1

已经在评论中回答了，但这里有一个例子。

父 pom：

<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
  <modelVersion>4.0.0</modelVersion>

  <groupId>com.essexboy</groupId>
  <artifactId>parent</artifactId>
  <version>1.0-SNAPSHOT</version>
  <packaging>pom</packaging>

  <modules>
    <module>jar1</module>
    <module>jar2</module>
  </modules>

</project>

和2个child/modules个poms，只有artifactId不同：

<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
  <modelVersion>4.0.0</modelVersion>

  <parent>
    <artifactId>parent</artifactId>
    <groupId>com.essexboy</groupId>
    <version>1.0-SNAPSHOT</version>
  </parent>

  <artifactId>jar1</artifactId>

  <dependencies>
    <dependency>
      <groupId>junit</groupId>
      <artifactId>junit</artifactId>
      <version>4.11</version>
      <scope>test</scope>
    </dependency>
  </dependencies>

  <build>
  </build>
</project>

额外信息

我用命令创建了父级：

mvn archetype:generate -DarchetypeGroupId=org.codehaus.mojo.archetypes -DarchetypeArtifactId=pom-root -DarchetypeVersion=RELEASE

然后用命令

创建了2个模块

mvn archetype:generate -DarchetypeGroupId=org.apache.maven.archetypes -DarchetypeArtifactId=maven-archetype-quickstart -DarchetypeVersion=RELEASE

如果您必须有一个 jar 项目（没有模块和父项目），您可以使用 shade-plugin:

<?xml version="1.0" encoding="UTF-8"?>

<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
    <modelVersion>4.0.0</modelVersion>

    <groupId>com.essexboy</groupId>
    <artifactId>double-jar</artifactId>
    <version>1.0-SNAPSHOT</version>

    <name>double-jar</name>

    <dependencies>
        <dependency>
            <groupId>junit</groupId>
            <artifactId>junit</artifactId>
            <version>4.11</version>
            <scope>test</scope>
        </dependency>
    </dependencies>

    <build>
        <plugins>
            <plugin>
                <groupId>org.apache.maven.plugins</groupId>
                <artifactId>maven-shade-plugin</artifactId>
                <version>3.2.1</version>
                <executions>
                    <execution>
                        <id>1</id>
                        <phase>package</phase>
                        <goals>
                            <goal>shade</goal>
                        </goals>
                        <configuration>
                            <finalName>jar1</finalName>
                            <filters>
                                <filter>
                                    <artifact>*:*</artifact>
                                    <excludes>
                                        <exclude>com/essexboy/App2*</exclude>
                                    </excludes>
                                </filter>
                            </filters>
                        </configuration>
                    </execution>
                    <execution>
                        <id>2</id>
                        <phase>package</phase>
                        <goals>
                            <goal>shade</goal>
                        </goals>
                        <configuration>
                            <finalName>jar2</finalName>
                            <filters>
                                <filter>
                                    <artifact>*:*</artifact>
                                    <excludes>
                                        <exclude>com/essexboy/App1*</exclude>
                                    </excludes>
                                </filter>
                            </filters>
                        </configuration>
                    </execution>
                </executions>
            </plugin>
        </plugins>
    </build>
</project>

Answer 2

我接受上面的答案是正确的，因为这是正确的做法，但如果像我这样的疯狂孩子试图以错误的方式去做，方法如下：

<plugin>
                <groupId>org.apache.maven.plugins</groupId>
                <artifactId>maven-jar-plugin</artifactId>
                <version>2.4</version>
                <executions>
                    <execution>
                        <id>first-jar</id>
                        <goals>
                            <goal>jar</goal>
                        </goals>
                        <configuration>
                            <classifier>first-jar</classifier>
                            <includes>
                                <include>first/FirstMain.class</include>
                                <include>log4j.properties</include>
                                <include>pictures/12px-Commons-logo.svg.png</include>
                                <include>textFiles/first.txt</include>
                            </includes>
                        </configuration>
                    </execution>
    </plugin>

注意使用 class 而不是 java，因为它使用编译扩展！至于其他文件，它们是class路径

上的资源

Maven - 为 java 项目中的每个 java 包创建一个 jar

Maven - creating a jar for every java package in java project

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jar

maven-plugin