OCP 7 II 正则表达式

Question

import java.util.regex.*;

public class Regex2 {

    public static void main(String[] args) {
        Pattern p = Pattern.compile("\d*");
        Matcher m = p.matcher("ab34ef");
        boolean b = false;
        while ( m.find()) {
            System.out.print(m.start() + m.group());
        }
    }
}

为什么这段代码会产生输出：01234456

Answer 1

\d* means integer 0 or more times.So an empty string between a and b ,before a ...those are also

matched.Use `\d+` to get correct result.

查看演示。

https://www.regex101.com/r/fG5pZ8/25

Answer 2

@vks 是对的：如果您使用 \d* 它适用于每个字符：

Index: char = matching:
    0: 'a'  = "" because no integer
    1: 'b'  = "" because no integer
    2: '3'  = "34" because there is two integer between index [2-3]
       '4'    is not checked because the index has been incremented in previous check.
    4: 'e'  = ""
    5: 'f'  = "" because no integer
    6: ''   = "" IDK

它产生 0, "", 1, "", 2, "34", 4, "", 5, "", 6, "" = 01234456 (这就是你得到它的原因）。

如果您使用 \d+，则只有具有一个或多个整数的组才会匹配。

Answer 3

因为\d*表示零个或多个数字。

作为，

OCP 7 II 正则表达式

OCP 7 II regular expression

java

regex