当两列具有相同的值时如何获取最后一条记录？

Question

我想在 gr_number 和课程

的基础上获得基于 Updated_ts 的最后一行

我正在使用以下查询。

select t.*
from (select  st.gr_number,st.course,st.is_active_flg,st.status,st.updated_ts

       ,sum(case when st.status = 'COMPLETED' then 1 else 0 end) over (partition by st.gr_number) as completedCourse,
      sum(case when st.status <> 'COMPLETED' and st.status <> 'APPLICATION' and st.is_active_flg = 'N' then 1 else 0 end) over (partition by st.gr_number) as IncompletCourse
      from admission_log st     
      join course cr on cr.course_id=st.course
      order by st.gr_number,st.course,st.updated_ts
     ) t
where completedCourse > 0 and IncompletCourse > 0;

这个查询给我的结果是

从上面的结果我只想要最后一个值与相同的 gr_number 和基于 Updated_ts

的课程

喜欢

请帮忙

Answer 1

我想你可以使用 row_number():

select t.*
from (select st.gr_number, st.course, st.is_active_flg, st.status, st.updated_ts,
            sum(case when st.status = 'COMPLETED'
                     then 1 else 0 
                end) over (partition by st.gr_number) as completedCourse,
            sum(case when st.status <> 'COMPLETED' and st.status <> 'APPLICATION' and st.is_active_flg = 'N'
                     then 1 else 0
                end) over (partition by st.gr_number) as IncompletCourse,
            row_number() over (partition by st.gr_number order by updated_ts desc) as seqnum
      from admission_log st join    
           course cr
           on cr.course_id = st.course
     ) t
where completedCourse > 0 and IncompletCourse > 0 and
      seqnum = 1;

我认为不需要您的 where 过滤器，但我已将它们留在里面。

当两列具有相同的值时如何获取最后一条记录？

how to get the last record when two columns have same values?

sql

oracle

greatest-n-per-group