根据发行和日期显示不同的总数

Question

我的查询结果如下：

以上示例数据：

declare @tbl table (DateOfService date, IssueID int, IssueName varchar(100), AssignedConsultant varchar(30), Activity varchar(100), TimeSpent float, TimeInvoiced float)

insert into @tbl (DateOfService,IssueID,IssueName,AssignedConsultant,Activity,TimeSpent,TimeInvoiced) values ('2019-12-19',10295,'Bin Issue','Doug','Activity Detail 1…',10.25,8)
insert into @tbl (DateOfService,IssueID,IssueName,AssignedConsultant,Activity,TimeSpent,TimeInvoiced) values ('2019-12-19',10295,'Bin Issue','Doug','Activity Detail 2…',10.25,8)
insert into @tbl (DateOfService,IssueID,IssueName,AssignedConsultant,Activity,TimeSpent,TimeInvoiced) values ('2020-01-24',10295,'Bin Issue','Doug','Activity Detail 3…',5.5,4)
insert into @tbl (DateOfService,IssueID,IssueName,AssignedConsultant,Activity,TimeSpent,TimeInvoiced) values ('2020-01-24',10295,'Bin Issue','Doug','Activity Detail 4…',5.5,4)

select
*
from    @tbl

出于保密原因，我无法分享我的查询，但是，

如何将这些结果更改为如下所示：

从我的预期结果可以看出，我只需要每个日期花费和开具发票的总时间。

我遇到的问题是，此结果在 Excel 中的一个枢轴中使用，导致反映双精度值。

请帮忙？

Answer 1

我认为这行不通，但看起来对这些结果有效。

这是我的想法（不确定技术上是否正确），但对我有用：

declare @tbl table (DateOfService date, IssueID int, IssueName varchar(100), AssignedConsultant varchar(30), Activity varchar(100), TimeSpent float, TimeInvoiced float)

insert into @tbl (DateOfService,IssueID,IssueName,AssignedConsultant,Activity,TimeSpent,TimeInvoiced) values ('2019-12-19',10295,'Bin Issue','Doug','Activity Detail 1…',10.25,8)
insert into @tbl (DateOfService,IssueID,IssueName,AssignedConsultant,Activity,TimeSpent,TimeInvoiced) values ('2019-12-19',10295,'Bin Issue','Doug','Activity Detail 2…',10.25,8)
insert into @tbl (DateOfService,IssueID,IssueName,AssignedConsultant,Activity,TimeSpent,TimeInvoiced) values ('2020-01-24',10295,'Bin Issue','Doug','Activity Detail 3…',5.5,4)
insert into @tbl (DateOfService,IssueID,IssueName,AssignedConsultant,Activity,TimeSpent,TimeInvoiced) values ('2020-01-24',10295,'Bin Issue','Doug','Activity Detail 4…',5.5,4)

select
    DateOfService
,   IssueID
,   IssueName
,   AssignedConsultant
,   Activity
,   case when lag(TimeSpent) over (order by IssueName) = TimeSpent then 0 else TimeSpent end            TimeSpent
,   case when lag(TimeInvoiced) over (order by IssueName) = TimeInvoiced then 0 else TimeInvoiced end   TimeInvoiced
from    @tbl

在db<>fiddle

中查看结果

Answer 2

我假设您有一些方法来识别每一行，所以我将 ID 列添加到 table 变量。我还将次要行的值保留为 NULL，因为您不清楚那里想要什么值。无论如何，这应该适用于表示的数据集：

declare @tbl table (ID int,DateOfService date, IssueID int, IssueName varchar(100), AssignedConsultant varchar(30), Activity varchar(100), TimeSpent float, TimeInvoiced float)

insert into @tbl (ID,DateOfService,IssueID,IssueName,AssignedConsultant,Activity,TimeSpent,TimeInvoiced) values (1,'2019-12-19',10295,'Bin Issue','Doug','Activity Detail 1…',10.25,8)
insert into @tbl (ID,DateOfService,IssueID,IssueName,AssignedConsultant,Activity,TimeSpent,TimeInvoiced) values (2,'2019-12-19',10295,'Bin Issue','Doug','Activity Detail 2…',10.25,8)
insert into @tbl (ID,DateOfService,IssueID,IssueName,AssignedConsultant,Activity,TimeSpent,TimeInvoiced) values (3,'2020-01-24',10295,'Bin Issue','Doug','Activity Detail 3…',5.5,4)
insert into @tbl (ID,DateOfService,IssueID,IssueName,AssignedConsultant,Activity,TimeSpent,TimeInvoiced) values (4,'2020-01-24',10295,'Bin Issue','Doug','Activity Detail 4…',5.5,4)


;WITH CTE AS (
SELECT MIN(ID) ID, DateOfService
FROM @tbl
GROUP BY DateOfService
)
SELECT T1.DateOfService,
        IssueID,
        IssueName,
        AssignedConsultant,
        Activity, 
        CASE WHEN T2.ID IS NULL THEN NULL ELSE T1.TimeSpent END TimeSpent,
        CASE WHEN T2.ID IS NULL THEN NULL ELSE T1.TimeInvoiced END TimeInvoiced
FROM @tbl T1
LEFT JOIN CTE T2 on T1.ID = T2.ID

根据发行和日期显示不同的总数

Show distinct totals based on Issue & Date

tsql

sql-server-2017