共享同一对象实例：Auryn 与 PHP-DI

Question

我正在尝试构建我的第一个无框架 PHP 应用程序并且我正在关注 this tutorial。我对教程中描述的一些概念比较陌生。尽管如此，我还是决定使用 PHP-DI instead of the suggested one (rdlowrey/auryn) 作为依赖注入器。

除了文件 Bootstrap.php（和文件 Dependencies.php:

之外，我已经根据教程创建了所有内容

<?php declare(strict_types = 1);

require(__DIR__ . '/../vendor/autoload.php');

...

$container = include('Dependencies.php');
$request = $container->make('Http\HttpRequest');
$response = $container->make('Http\HttpResponse');

...

switch ($routeInfo[0]) {
    ...
    case \FastRoute\Dispatcher::FOUND:
        $className = $routeInfo[1][0];
        $method = $routeInfo[1][1];
        $vars = $routeInfo[2];

        $class = $container->make($className);
        $class->$method($vars); // (**)
        break;
}

echo $response->getContent(); // (*)

$class 只能是 Homepage class 的一个实例，它只有一个方法 (show())，在 (**) 中调用：

class Homepage
{
    private $request;
    private $response;
    private $renderer;

    public function __construct(
        Request $request, 
        Response $response,
        Renderer $renderer
    ) {
        $this->request = $request;
        $this->response = $response;
        $this->renderer = $renderer;
    }

    public function show() {
        $data = [
            'name' => $this->request->getParameter('name', 'stranger'),
        ];
        $html = $this->renderer->render('Homepage', $data);
        $this->response->setContent($html); // (***)
    }
}

综上所述，应用程序 returns 一个带有空主体的 200 HTTP 响应 [此处 (*)] 但是如果我尝试在 (***) 之后打印 HTTP 响应的内容，我会得到正确的响应。这可能意味着 HttpResponse class 有两个不同的实例。（对吗？）

教程的作者rdlowrey/auryn使用方法share()在classes之间共享同一个HttpReponse实例，如"original"所示Dependencies.php 文件：

<?php declare(strict_types = 1);
use \Auryn\Injector;
...
$injector = new Injector;
$injector->alias('Http\Response', 'Http\HttpResponse');
$injector->share('Http\HttpResponse');
...
return $injector;

有没有办法使用 PHP-DI（具有 PHP 定义）获得相同的行为？

这是我的 Dependencies.php 版本：

<?php declare(strict_types = 1);

$definitions = [
    'Http\Request' => DI\create('Http\HttpRequest')->constructor(
        $_GET, $_POST, $_COOKIE, $_FILES, $_SERVER),
    'Http\HttpRequest' => function () {
        $r = new Http\HttpRequest($_GET, $_POST, $_COOKIE, $_FILES, $_SERVER);
        return $r;
    },
    'Http\Response' => DI\create('Http\HttpResponse'),

    'Twig\Environment' => function () {
        $loader = new Twig\Loader\FilesystemLoader(
            dirname(__DIR__) . '/templates');
        $twig = new Twig\Environment($loader);
        return $twig;
    },

    'Example\Template\TwigRenderer' => function (Twig\Environment $renderer) {
        return new Example\Template\TwigRenderer($renderer);
    },
    'Example\Template\Renderer' => DI\create(
        'Example\Template\TwigRenderer')->constructor(
            DI\get('Twig\Environment')),
];

$containerBuilder = new DI\ContainerBuilder;
$containerBuilder->addDefinitions($definitions);
$container = $containerBuilder->build();
return $container;

Answer 1

在 Bootstrap.php 中，获取 (get()) HttpRequest/HttpResponse 个实例，而不是创建 (make()) 个实例，解决了问题。

...
$container = include('Dependencies.php');
$request = $container->get('Http\HttpRequest');
$response = $container->get('Http\HttpResponse');
...

正如 documentation 中明确指出的那样：

The make() method works like get() except it will resolve the entry every time it is called. [..] if the entry is an object, an new instance will be created every time [..]

共享同一对象实例：Auryn 与 PHP-DI

Sharing the same instance of an object: auryn vs. PHP-DI

php

dependency-injection

php-di

no-framework

auryn