如何忽略自动生成的属性并在其位置添加新属性？

Question

我正在创建一个 XML 使用序列化的节点，使用 C#

<node xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<childNode1><![CDATA[some file name]]></childNode1>
<childNode2><![CDATA[some file name]]></childNode2>
</node >

如何避免“节点”的属性 "xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" 并在其位置添加其他属性？因此，结果节点应如下所示：

<node name="xyz" group="abc">

我使用的代码是：

class Program
{
    public static void Main(string[] args)
    {
        AddressDetails details = new AddressDetails();
        Serialize(details);
    }

    static public void Serialize(AddressDetails details)
    {

        XmlSerializer serializer = new XmlSerializer(typeof(AddressDetails));
        TextWriter writer = new StreamWriter(@"C:\Xml.xml");
        serializer.Serialize(writer, details);
    }
}
public class AddressDetails
{ 
    [XmlElement("Street")]
    public string StreetName { get; set; }
    [XmlElement("CityName")]
    public string City { get; set; }
    public Address address;
    public AddressDetails()
    {
        StreetName = "XYZ";
        City = "Pune";
    }
    public System.Xml.XmlCDataSection MyStringCDATA
    {
        get
        {
            return new System.Xml.XmlDocument().CreateCDataSection("load and run");
        }
        set
        {  }
    }
}
public class Address
{
    [XmlAttribute("HouseNo")]
    public int HouseNo { get; set; }
    [XmlAttribute("floor")]
    public int floor { get; set; }
    public Address()
    {
        HouseNo = 204;
        floor = 2;
    }
}

创建这个xml的目的是，我想多次创建相同的节点模板，但每个节点名称都不同，我想动态给出节点名称。例如。在上面的代码中，节点名称是通过 class 名称设置的 "AddressDetails" .....现在我希望节点名称为 "AddressDetails_John"..."AddressDetails_Harry".. 是否有任何规定以这种方式使其动态化？ –

谢谢...

Answer 1

要禁止写入标准 XML 命名空间，将空的 XmlSerializerNamespaces 传递给 XmlSerializer.Serialize():

    XmlSerializerNamespaces ns = new XmlSerializerNamespaces();
    ns.Add("", ""); // Disable the xmlns:xsi and xmlns:xsd lines.
    serializer.Serialize(xmlWriter, obj, ns);

添加一个属性：当一个属性被标记为[XmlAttribute]属性时，它会被序列化为XML作为一个属性，例如：
```
    [XmlAttribute("name")]
    public string Name { get; set; }
```

因此，在您的示例中，如果您希望 AddressDetails.Street 和 AddressDetails.CityName 成为属性，您可以这样做：

public class AddressDetails
{
    [XmlAttribute("Street")]
    public string StreetName { get; set; }

    [XmlAttribute("CityName")]
    public string City { get; set; }

    public Address address;

    public AddressDetails()
    {
        StreetName = "XYZ";
        City = "Pune";
    }

    public System.Xml.XmlCDataSection MyStringCDATA
    {
        get
        {
            return new System.Xml.XmlDocument().CreateCDataSection("load and run");
        }
        set
        { }
    }
}

并且，要在序列化时省略标准名称空间，您可以添加以下静态方法：

    public static void Serialize<T>(T obj, string filename, bool omitStandardNamespaces = false)  // Change the default to true if you prefer.
    {
        using (var textWriter = new StreamWriter(filename))
        {
            XmlSerializer serializer = new XmlSerializer(typeof(T));
            XmlWriterSettings settings = new XmlWriterSettings();
            settings.Indent = true;        // For cosmetic purposes.
            settings.IndentChars = "    "; // For cosmetic purposes.
            using (var xmlWriter = XmlWriter.Create(textWriter, settings))
            {
                if (omitStandardNamespaces)
                {
                    XmlSerializerNamespaces ns = new XmlSerializerNamespaces();
                    ns.Add("", ""); // Disable the xmlns:xsi and xmlns:xsd lines.
                    serializer.Serialize(xmlWriter, obj, ns);
                }
                else
                {
                    serializer.Serialize(xmlWriter, obj);
                }
            }
        }
    }

如何忽略自动生成的属性并在其位置添加新属性？

How to neglect automatically generated attributes and add new attributes in its place?

c#

xml

xml-serialization