查找时间戳超过给定持续时间的相邻 CSV 行

Question

我有一个包含以下内容的文件：

"BatchID","BatchName","JobName","ScannerID","DateCreated","DailyCounter"
"12713","9001","fst100","09                  ","2/6/2020 6:21:06 AM","1"
"12714","9002","fst100","09                  ","2/6/2020 6:21:42 AM","2"
"12715","9003","fst100","09                  ","2/6/2020 6:21:58 AM","3"
"12716","9004","fst100","09                  ","2/6/2020 6:22:13 AM","4"
"12717","9005","fst100","09                  ","2/6/2020 6:22:30 AM","5"
"12718","9006","fst100","09                  ","2/6/2020 6:24:54 AM","6"
"12719","9007","fst100","09                  ","2/6/2020 6:25:12 AM","7"
"12720","9008","fst100","09                  ","2/6/2020 6:55:11 AM","8"
"12721","9009","fst100","09                  ","2/6/2020 6:55:27 AM","9"

我想比较日期创建字段并将相隔 15 分钟或更长时间的行写入文件。

Answer 1

开始于：

您的时间戳字符串采用的格式在您将它们转换为 [datetime] (System.DateTime) 时可以按原样识别（除非您的格式列出了天而不是月份），
你可以直接减去两个[datetime]实例得到一个[timespan]实例（System.TimeSpan），你可以.TotalMinutes 属性查询

解决方案相当简单：

$prevRow = $null
Import-Csv in.csv | ForEach-Object { # Parse the CSV rows into objects and process each
  if ($prevRow -and ([datetime] $_.DateCreated - [datetime] $prevRow.DateCreated).TotalMinutes -gt 15) {
    # Output the previous row and the current row.
    $prevRow; $_
  }
  $prevRow = $_
} # | Export-Csv -NoTypeInformation -Encoding Utf8 out.csv

^{以上将匹配的行打印到屏幕；删除 # 以导出到（不同的）CSV 文件。}

注意：如所写，您最终可能会在输出中得到重复行，即如果在相邻行 A B C 中 A 和 B 以及 B 和 C 都超过 15 分钟分开，此时输出 A B B C。

文档链接：

查找时间戳超过给定持续时间的相邻 CSV 行

Find adjacent CSV rows whose timestamps exceed a given duration

powershell

date

compare

timespan