遍历 XML 并选择特定的元素树内容

Question

我有一个 XML 看起来像这样：

<openie>
  <triple confidence="1.000">
    <subject begin="0" end="1">
      <text>PAF</text>
      <lemma>paf</lemma>
    </subject>
    <relation begin="1" end="2">
      <text>gets</text>
      <lemma>get</lemma>
    </relation>
    <object begin="2" end="6">
      <text>name of web site</text>
      <lemma>name of web site</lemma>
    </object>
  </triple>
  <triple confidence="1.000">
    <subject begin="0" end="1">
      <text>PAF</text>
      <lemma>paf</lemma>
    </subject>
    <relation begin="1" end="2">
      <text>gets</text>
      <lemma>get</lemma>
    </relation>
    <object begin="2" end="3">
      <text>name</text>
      <lemma>name</lemma>
    </object>
  </triple>
</openie>

元素 openie 嵌套在此处：root>document>sentences>sentence>openie

在我的函数中，我试图打印 triples，每个都包含 subject, relation, object 元素。不幸的是，我无法让它工作，因为我无法进入这三个元素及其 text 元素。哪一部分是错误的？

def get_openie():
    print('OpenIE parser start...')
    tree = ET.parse('./tmp/nlp_output.xml')
    root = tree.getroot()
    for triple in root.findall('./document/sentences/sentence/openie/triple'):
        t_subject = triple.find('subject/text').text
        t_relation = triple.find('relation/text').text
        t_object = triple.get('object/text').text
        print(t_subject,t_relation,t_object)

两个三元组的输出应如下所示：

PAF gets name of web site

PAF gets name

Answer 1

要获得 t_object，您是运行 triple.get() 而不是 triple.find()。更改它可以解决您的问题。

def get_openie():
    print('OpenIE parser start...')
    tree = ET.parse('./tmp/nlp_output.xml')
    root = tree.getroot()
    for triple in root.findall('./document/sentences/sentence/openie/triple'):
        t_subject = triple.find('subject/text').text
        t_relation = triple.find('relation/text').text
        t_object = triple.find('object/text').text
        print(t_subject,t_relation,t_object)

遍历 XML 并选择特定的元素树内容

Iterating over XML and selecting specific element tree content

python

xml

xml-parsing