两个按钮在 csv 问题中打开相同的 table？

Question

这是两个按钮

second_year_icon = tk.PhotoImage(file = r"D:\Academy Management Application\Iconsnd_year_icon.png")
global second_year_btn
second_year_btn = tk.Button(label_frame, font=LARGE_FONT, image=second_year_icon,
                      border=0 ,command=lambda : controller.show_frame(second_year) )
second_year_btn.grid(row=0 , column =0, padx=(10,10) , pady=(10,0), sticky=tk.E)


first_year_icon=tk.PhotoImage(file = r"D:\Academy Management 
Application\Iconsst_year_icon.png")

        global first_year_btn
        first_year_btn = tk.Button(label_frame, font=LARGE_FONT, image=first_year_icon
                            , command=lambda : controller.show_frame(second_year), border=0 )
        first_year_btn.grid(row=0 , column =1, padx=(10,10) , pady=(10,0), sticky=tk.E)

现在，如果单击 first_year_btn，它也会在我单击 second_year_btn 时显示相同的数据。我知道我犯了一些愚蠢的错误，但不知道是哪一个。我很紧张。任何人都可以帮助我吗？

reader = DictReader(f, delimiter=',')
    for row in reader:
        if first_year_btn:
            if row['Class Name'] == '09th':
                registration_no= row['Registration No']
                student_name = row['Student Name']
                f_name = row['Father Name']
                gender = row['Gender']
                class_name =row['Class Name']
                class_session =row['Class Session']
                admission_date =row['Admission Date']
                monthly_fee = row['Monthly Fee']
                dues_payment=row['Dues']
                tree.insert("", 0, values=(registration_no, student_name, f_name,gender,class_name,class_session,admission_date,monthly_fee,dues_payment))
        elif  second_year_btn :

            if row['Class Name'] == 'Second Year':
                registration_no = row['Registration No']
                student_name = row['Student Name']
                f_name = row['Father Name']
                gender = row['Gender']
                class_name = row['Class Name']
                class_session = row['Class Session']
                admission_date = row['Admission Date']
                monthly_fee = row['Monthly Fee']
                dues_payment = row['Dues']
                tree.insert("", 0, values=(
                registration_no, student_name, f_name, gender, class_name, class_session, admission_date,
                monthly_fee, dues_payment))

Answer 1

遵循这种结构，MainFrameClass 是您的旧class，它来自库或为您创建一个旧框架。它有一些在该框架内使用的变量。您的任务是创建新的 class，将旧的继承为新的。创建新方法，通过该方法您只能更改要在框架内更改的那些变量。

class MainFrameClass:

    def __init__(self, name):
        self.name = name

    def say_hi(self):
        print("Hi, I am " + self.name)

class UpdatedClass(MainFrameClass):

    def show_name(self):
        print("Hi, I am " + self.name)

    def update_name(self,new_name):
        self.name = new_name

x = MainFrameClass("Old Variable Data Coming from Old Class")
y = UpdatedClass("New Variable Data Given to New Class")



y.show_name()
y.update_name('New Variable Data That was Updated Again')
y.show_name()

Answer 2

下面是一个基于您发布的代码的简单示例：

import tkinter as tk
from tkinter import ttk
from csv import DictReader

class App(tk.Tk):
  def __init__(self):
    super().__init__()

    mainframe = tk.Frame(self)
    mainframe.pack(fill=tk.BOTH, expand=1)

    mainframe.rowconfigure(0, weight=1)
    mainframe.columnconfigure(0, weight=1)

    self.frames = {}
    for f in (main_page, second_year):
      frame = f(mainframe, self)
      frame.grid(row=0, column=0, sticky='nsew')
      self.frames[f] = frame
    self.show_frame(main_page)

  def show_frame(self, fclass):
      frame = self.frames[fclass]
      frame.tkraise()
      return frame

class main_page(tk.Frame):
  def __init__(self, parent, controller):
    super().__init__(parent)
    self.controller = controller

    label_frame = tk.Frame(self)
    label_frame.pack(fill=tk.BOTH, expand=1)

    first_year_button = tk.Button(label_frame, text='First Year',
                                  width=20, command=lambda: self.select_year(1))
    first_year_button.grid(row=0, column=0, padx=10, pady=(10,0))

    second_year_button = tk.Button(label_frame, text='Second Year',
                                   width=20, command=lambda: self.select_year(2))
    second_year_button.grid(row=0, column=1, padx=10, pady=(10,0))

  def select_year(self, year):
    frame = self.controller.show_frame(second_year)
    frame.set_year(year)

class second_year(tk.Frame):
  def __init__(self, parent, controller):
    super().__init__(parent)

    columns = ('Reg #', 'Student Name', 'Father Name', 'Gender',
               'Class', 'Session', 'Admin. Fee', 'Monthly Fee', 'Dues')
    self.tree = ttk.Treeview(self, show='headings', columns=columns)
    self.tree.pack(fill=tk.BOTH, expand=1)

    for col in columns:
      self.tree.heading(col, text=col)
      self.tree.column(col, width=100, anchor='c')

  def set_year(self, year):
    if year == 1:
      filter = '09th'
    elif year == 2:
      filter = 'Second Year'
    else:
      filter = None
    if filter:
      with open('registration.csv', newline='') as f:
        reader = DictReader(f, delimiter=',')
        for row in reader:
          if row['Class Name'] == filter:
            registration_no= row['Registration No']
            student_name = row['Student Name']
            f_name = row['Father Name']
            gender = row['Gender']
            class_name = row['Class Name']
            class_session = row['Class Session']
            admission_date = row['Admission Date']
            monthly_fee = row['Monthly Fee']
            dues_payment = row['Dues']
            self.tree.insert('', 0, values=(registration_no, student_name, f_name, gender,
                                            class_name, class_session, admission_date,
                                            monthly_fee, dues_payment))

app = App()
app.mainloop()

两个按钮在 csv 问题中打开相同的 table？

Both buttons opens same table in csv problem?

python

csv

tk

tkinter

python-3.x