JavaScript canvas drawImage getImageData
JavaScript canvas drawImage getImageData
我无法理解 2 种方法如何与 canvas 一起工作:
绘制图像
获取图像数据
事实上,我想将位图图像解析为 RGBA 点数组,能够使用 putImageData 方法对其进行转换和显示。
但只有一件事有效:drawImage 或 getImageData。
我寻求帮助 - 解释这些方法如何相互影响。
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title> Canvas to array </title>
</head>
<body>
<canvas id="canvas" width="1200" height="600" />
<script>
"use strict"
let imageData;
let My_img = new Image();
My_img.src = 'test1.jpg';
let cnv = document.getElementById("canvas");
let ctx = cnv.getContext("2d");
My_img.onload = function() {
ctx.drawImage(My_img, 0, 0);
imageData = ctx.getImageData(0, 0, canvas.width, canvas.height);
for (let i=0; i<imageData.data.length; i+=4){
imageData.data[i]=0;
imageData.data[i+1]=255;
imageData.data[i+2]=0;
imageData.data[i+3]=222;
}
ctx.putImageData(imageData,300,300);
};
</script>
</body>
</html>
您需要将图像对象的跨源标志设置为"Anonymous"。
My_img.crossOrigin = "Anonymous";
另请参阅:How to fix getImageData() error The canvas has been tainted by cross-origin data?
演示
let ctx = document.getElementById("canvas").getContext("2d");
let img = new Image();
img.crossOrigin = "Anonymous";
img.src = 'https://placekitten.com/200/138';
img.onload = function() {
ctx.drawImage(img, 0, 0);
setTimeout(() => filterImage(ctx), 1000);
};
// Multiply the value of the red channel by 2 and the blue channel by 3.
function filterImage(ctx) {
let d = ctx.getImageData(0, 0, ctx.canvas.width, ctx.canvas.height);
for (let i = 0; i < d.data.length; i += 4) {
d.data[i + 0] = Math.min(Math.floor(d.data[i + 0] * 2.0), 0xFF); // R
d.data[i + 1] = Math.min(Math.floor(d.data[i + 1] * 1.0), 0xFF); // G
d.data[i + 2] = Math.min(Math.floor(d.data[i + 2] * 3.0), 0xFF); // B
d.data[i + 3] = 0xFF; // A
}
ctx.putImageData(d, 0, 0);
}
<canvas id="canvas" width="200" height="138" />
我无法理解 2 种方法如何与 canvas 一起工作: 绘制图像 获取图像数据 事实上,我想将位图图像解析为 RGBA 点数组,能够使用 putImageData 方法对其进行转换和显示。 但只有一件事有效:drawImage 或 getImageData。 我寻求帮助 - 解释这些方法如何相互影响。
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title> Canvas to array </title>
</head>
<body>
<canvas id="canvas" width="1200" height="600" />
<script>
"use strict"
let imageData;
let My_img = new Image();
My_img.src = 'test1.jpg';
let cnv = document.getElementById("canvas");
let ctx = cnv.getContext("2d");
My_img.onload = function() {
ctx.drawImage(My_img, 0, 0);
imageData = ctx.getImageData(0, 0, canvas.width, canvas.height);
for (let i=0; i<imageData.data.length; i+=4){
imageData.data[i]=0;
imageData.data[i+1]=255;
imageData.data[i+2]=0;
imageData.data[i+3]=222;
}
ctx.putImageData(imageData,300,300);
};
</script>
</body>
</html>
您需要将图像对象的跨源标志设置为"Anonymous"。
My_img.crossOrigin = "Anonymous";
另请参阅:How to fix getImageData() error The canvas has been tainted by cross-origin data?
演示
let ctx = document.getElementById("canvas").getContext("2d");
let img = new Image();
img.crossOrigin = "Anonymous";
img.src = 'https://placekitten.com/200/138';
img.onload = function() {
ctx.drawImage(img, 0, 0);
setTimeout(() => filterImage(ctx), 1000);
};
// Multiply the value of the red channel by 2 and the blue channel by 3.
function filterImage(ctx) {
let d = ctx.getImageData(0, 0, ctx.canvas.width, ctx.canvas.height);
for (let i = 0; i < d.data.length; i += 4) {
d.data[i + 0] = Math.min(Math.floor(d.data[i + 0] * 2.0), 0xFF); // R
d.data[i + 1] = Math.min(Math.floor(d.data[i + 1] * 1.0), 0xFF); // G
d.data[i + 2] = Math.min(Math.floor(d.data[i + 2] * 3.0), 0xFF); // B
d.data[i + 3] = 0xFF; // A
}
ctx.putImageData(d, 0, 0);
}
<canvas id="canvas" width="200" height="138" />