c ++显式构造函数不阻止double到int的转换

Question

我有一个从 int 到 class C 的构造函数和一个从 double 到

我让第一个进行隐式类型转换，但使用关键字 explicit 阻止了第二个。

但是，不幸的是，出现了 double 到 int 的隐式转换。我能以某种方式阻止它吗？

这是一个简化的例子

//g++  5.4.0
#include <iostream>
using namespace std;

class C{
    int* tab;
    public:
    C():tab(nullptr){ cout<<"(void)create zilch\n"; }
    C(int size):tab(new int[size]){ cout<<"(int)create " << size << "\n"; }
    explicit C(double size):tab(new int[(int)size]){ cout<<"(double)create " << size << "\n"; }
    ~C(){ if(tab) {cout<<"destroy\n"; delete[] tab;} else cout <<"destroy zilch\n"; }
};    

int main()
{
    cout << "start\n";
    {
        C o1(1);
        C o2 = 2; //ok, implicit conversion allowed
        C o3(3.0);
        C o4 = 4.0; //ko, implicit conversion to double blocked... but goes to int 
    }
    cout << "stop\n";
}

//trace 
//
//start
//(int)create 1
//(int)create 2
//(double)create 3
//(int)create 4
//destroy
//destroy
//destroy
//destroy
//stop

Answer 1

嗯！ Eljay 在评论中速度更快，但这是最终代码，它会让您在尝试隐式使用 double 时遇到编译错误

#include <iostream>
using namespace std;

class C{
    int* tab;

public:
    //THE TRICK: block any implicit conversion by default
    template <class T> C(T) = delete;

    C():tab(nullptr){ cout<<"(void)create zilch\n"; }
    C(int size):tab(new int[size]){ cout<<"(int)create " << size << "\n"; }
    explicit C(double size):tab(new int[(int)size]){ cout<<"(double)create " << size << "\n"; }
    ~C(){ if(tab) {cout<<"destroy\n"; delete[] tab;} else cout <<"destroy zilch\n"; }
};

int main()
{
    cout << "start\n";
    {
        C o1(1);
        C o2 = 2; //ok, implicit conversion allowed
        C o3(3.0);
        C o4 = 4.0; //ko, implicit conversion to other types deleted
        C o5 = (C)5.0; //ok. explicit conversion
    }
    cout << "stop\n";
}

Answer 2

您可以尝试将 C(int) 构造函数替换为使用启用类型特征的构造函数，例如

#include <iostream>
#include <type_traits>
using namespace std;

class C{
    int* tab;
    public:
    C():tab(nullptr){ cout<<"(void)create zilch\n"; }
    template<typename I, typename = typename enable_if<is_integral<I>::value>::type>
    C(I size):tab(new int[size]){ cout<<"(int)create " << size << "\n"; }
    explicit C(double size):tab(new int[(int)size]){ cout<<"(double)create " << size << "\n"; }
    ~C(){ if(tab) {cout<<"destroy\n"; delete[] tab;} else cout <<"destroy zilch\n"; }
};

int main()
{
    cout << "start\n";
    {
        C o1(1);
        C o2 = 2; //ok, implicit conversion allowed
        C o3(3.0);
        C o4 = 4.0; //ko, implicit conversion to double blocked... but goes to int
    }
    cout << "stop\n";
}

这会给你这样的错误：

test.cpp: In function ‘int main()’:
test.cpp:22:16: error: conversion from ‘double’ to non-scalar type ‘C’ requested
         C o4 = 4.0; //ko, implicit conversion to double blocked... but goes to int
                ^

c ++显式构造函数不阻止double到int的转换

c++ explicit contructor not blocking double to int convertion

c++

explicit