将一个数字放入数组中,并将其从 char 转换为 int

Put a number in array, and convert it from char to int

输入一个数字,然后将每个数字放入一个数组中,我已经将其转换为一个字符串,以便我可以将它放入一个数组中,但是当我使用强制转换将其重新制作为 int i 时获取 ascii 码..

#include <stdio.h>
#include <stdlib.h>

int main(){

    char num_str[64] = {0};
    int num, cifra;

    printf("Write a number: \n");
    scanf("%d", &num);

    int len = snprintf(num_str, 64, "%d", num);
    printf("The length is %d\n", len);

    for(int i = 0; i < len; i++) {
        cifra = (int)(num_str[i]);
        printf("%d \n", cifra);
    }

    return 0;
}

convert it from char to int

测试数字字符并减去'0'

for(int i = 0; i < len; i++) {
    int cifra = num_str[i];
    if (cifra >= '0' && cifra <= '9') printf("%d\n", cifra - '0');
    else printf("%c\n", cifra);  // such as '-'
}