读取一个文件，计算定界符和输出不匹配定界符的行号

Question

我有一个名为：test_file.txt 的文件。第二行有 4 个竖线分隔符，除第二行外的所有其他行都有 3 个竖线分隔符。我只想输出第 2 行，因为它比其他行多了一个定界符。

$colCnt = "C:\test.txt"
[int]$LastSplitCount = $Null
Get-Content $colCnt | ?{$_} | Select -Skip 1 | %{if($LastSplitCount -and !

($_.split("|").Count -eq $LastSplitCount))

{"Process stopped at line number $($_.psobject.Properties.value[5]) for column count mis-match.";break}

elseif(!$LastSplitCount){$LastSplitCount = $_.split("|").Count}}

Answer 1

如果您的文本文件看起来像这样：

blah|using|three|delimiters
blah|using|four |delimiter |characters
blah|using|three|delimiters
blah|using|four |delimiter |characters
blah|using two  |delimiters

以下代码应输出多于（或少于）3 个 | 个分隔符的行：

$line = 0
switch -Regex -File "C:\test.txt" {
    '^(?:[^|]*\|){3}[^|]*$' { $line++ }   # this line is OK, just increase the line counter
    default { "Bad delimiter count in line {0}: '{1}'" -f ++$line, $_ }
}

输出：

Bad delimiter count in line 2: 'blah|using|four |delimiter |characters'
Bad delimiter count in line 4: 'blah|using|four |delimiter |characters'
Bad delimiter count in line 5: 'blah|using two  |delimiters'

正则表达式详细信息：

^           Assert position at the beginning of the string
(?:         Match the regular expression below
   [^|]     Match any character that is NOT a “|”
      *     Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
   \|       Match the character “|” literally
){3}        Exactly 3 times
[^|]        Match any character that is NOT a “|”
   *        Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
$           Assert position at the end of the string (or before the line break at the end of the string, if any)

读取一个文件，计算定界符和输出不匹配定界符的行号

Read a file, count delimiters and output line number with mismatched delimiter

powershell

count

delimiter

line-numbers