按多个关键字拆分字符串并创建字典

Question

在做了一些网络抓取之后，我终于能够从字体主体中获取一个字符串，结果如下

string = Date:  02/13/2020  Court Time:  1030  Court Room:  0206  Microfilm:  SD000000000

我需要弄清楚关于我的代码的最后一件事，我想这在这一点上看起来相当微不足道，就是将该字符串拆分为字典对，其中配对如下所示：

Date:  02/13/2020,
Court Time:  1030,  
Court Room:  0206,  
Microfilm:  SD000000000

我想也许可以做一些事情：

keywords = ['Date:','Court Time:','Court Room:', 'Microfilm:']
for k in keywords:
            print(string.split())

使用这些关键字作为分隔符。但它多次吐出这个

['Date:', '02/13/2020', 'Court', 'Time:', '1030', 'Court', 'Room:', '0206', 'Microfilm:', 'SD000000000']
['Date:', '02/13/2020', 'Court', 'Time:', '1030', 'Court', 'Room:', '0206', 'Microfilm:', 'SD000000000']
['Date:', '02/13/2020', 'Court', 'Time:', '1030', 'Court', 'Room:', '0206', 'Microfilm:', 'SD000000000']
['Date:', '02/13/2020', 'Court', 'Time:', '1030', 'Court', 'Room:', '0206', 'Microfilm:', 'SD000000000']

Answer 1

按照你的例子：

s='Date:  02/13/2020  Court Time:  1030  Court Room:  0206  Microfilm:  SD000000000'

假设双 space 是您的分隔符：

sep = '  '
lst = s.split(sep)
d = dict(zip(lst[0::2], lst[1::2]))

输出为：

 {'Date:': '02/13/2020',
  'Court Time:': '1030',
  'Court Room:': '0206',
  'Microfilm:': 'SD000000000'}

Answer 2

下面的一段代码可以解决问题。

my_string = "Date:  02/13/2020, Court Time:  1030, Court Room:  0206,  Microfilm:  SD000000000"
key_value_pair = [line.split(':') for line in my_string.split(',')]
output_dict = {k.strip(): v.strip() for k, v in key_value_pair}
print(output_dict)

输出：

{'Date': '02/13/2020', 'Court Time': '1030', 'Court Room': '0206', 'Microfilm': 'SD000000000'}

Answer 3

我会使用正则表达式并构建关键字列表的模式：

pattern = '|'.join(['(' + i + ')' for i in keywords])

这给出 '(Date:)|(Court Time:)|(Court Room:)|(Microfilm:)'

我们现在可以使用该模式拆分字符串：

lst = re.split(pattern, string)

到达这里：['', 'Date:', None, None, None, ' 02/13/2020 ', None, 'Court Time:', None, None, ' 1030 ', None, None, 'Court Room:', None, ' 0206 ', None, None, None, 'Microfilm:', ' SD000000000']

让我们post处理列表以提取最终字典的键和值：

def getkey(ls):
    for i in ls:
        if i is not None:
            return i.strip().rstrip(':')

lk = len(keywords)
elts = [(lst[i: i+lk)], lst[i+lk]) for i in range(1, len(lst), lk+1)]
resul = {getkey(i): j.strip() for i,j in elts}

这给出了预期的结果：

{'Date': '02/13/2020', 'Court Time': '1030', 'Court Room': '0206', 'Microfilm': 'SD000000000'}

按多个关键字拆分字符串并创建字典

Splitting a string by multiple keywords and creating a dict

python

string

dictionary

split

regex-group