JoinColumn Hibernate / API

JoinColumn Hibernate / API

我遇到了以下问题:我只想加入 table 市场(主要)和电话,但是在使用注释执行此操作时遇到了一些问题。

我只是想使用 Comercio.id 作为来自 Telefone.fk_id 的相应外键,但它无法识别它。我还想问一下是否需要为两者创建一个存储库接口 类。

编辑。此外,对于这样的示例,POST 请求看起来如何?

Comercio.java

@Entity
@Table(name = "comercio")
public class Comercio {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long id;
    private String nome;
    private String cnpj;
    private String endereco;

    @OneToMany(targetEntity = Telefone.class , mappedBy = "comercio", fetch = FetchType.LAZY)
    private List<Telefone> telefones;
    private String email;

Telefone.java

@Entity
@Table(name = "telefone")
public class Telefone {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long telefone_id;

    @ManyToOne
    @JoinColumn(name="fk_id", referencedColumnName = "id")
    private Comercio comercio;
    private String telefone;

我得到的答案:

{
      "nome" : "Americanas",
      "cnpj" : "000",
      "endereco" : "SQN 112",
      "telefones" : [ ],
      "email" : "contato@americanas.com",
      "comercio_id" : 1
}

控制台:

Hibernate: select comercio0_.id as id1_0_, comercio0_.cnpj as cnpj2_0_, comercio0_.email as email3_0_, comercio0_.endereco as endereco4_0_, comercio0_.nome as nome5_0_ from comercio comercio0_
Hibernate: select telefones0_.fk_id as fk_id3_1_0_, telefones0_.telefone_id as telefone1_1_0_, telefones0_.telefone_id as telefone1_1_1_, telefones0_.fk_id as fk_id3_1_1_, telefones0_.telefone as telefone2_1_1_ from telefone telefones0_ where telefones0_.fk_id=**?**

感谢任何帮助。

我建议电话本身不是一个实体:您永远不会想要查询电话,它只作为 Comercio 的一部分存在。

它可能是一个 Embeddable 而不是一个实体,但是因为它只有一个 属性 - 数字 - 然后您可以简化为下面并将其映射为字符串集合。那么就不需要 Telefone class.

@Entity
@Table(name = "comercio")
public class Comercio {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long id;
    private String nome;
    private String cnpj;
    private String endereco;

    @ELementCollection
    @CollectionTable(name = "comercio_telefone", 
                joinColumns=@JoinColumn(name="comercio_id"))
    private List<String> telefones;

    private String email;
}