如何使用 Python 从另一个列表中按列表项划分列表项？

Question

我想在两个列表中划分列表项。

a = [[1, 0, 2], [0, 0, 0], [1], [1]]
b = [[5, 6, 4], [6, 6, 6], [3], [3]]

如何将 a 除以 b 以获得此输出：

c = [[0.2, 0, 0.5], [0, 0, 0], [0.333], [0.333]]

谁能帮帮我？

Answer 1

压缩两个列表并使用列表理解：

from __future__ import division   # in python2 only
result = [[x/y for x,y in zip(xs, ys)] for xs, ys in zip(a, b)]

样本运行：

In [1]: a = [[1, 0, 2], [0, 0, 0], [1], [1]]
   ...: b = [[5, 6, 4], [6, 6, 6], [3], [3]]
   ...: 

In [2]: result = [[x/y for x,y in zip(xs, ys)] for xs, ys in zip(a, b)]

In [3]: result
Out[3]: [[0.2, 0.0, 0.5], [0.0, 0.0, 0.0], [0.3333333333333333], [0.3333333333333333]]

Answer 2

使用 itertools.izip (Python2.7):

import itertools

[[float(aaa) / bbb for (aaa, bbb) in itertools.izip(aa, bb)] \
    for (aa, bb) in itertools.izip(a, b)]

Answer 3

from __future__ import division # for Python2

[[x / y for x, y  in zip(*item)] for item in zip(a, b)]

如何使用 Python 从另一个列表中按列表项划分列表项？

How to divide list item by list item from another list using Python?

python

list

division