如何获得按名称分组的时差持续时间总计以及价值何时以某种方式变化？

Question

我正在寻找值最初 1 现在为 0 的行之间的时间值差异总和，按名称分组。

单个姓名的示例数据，但实际数据中有许多不同的姓名。

+--------+---------------+---------------------+--------+
| RowNum |     Name      |      Timestamp      | Value  |
+--------+---------------+---------------------+--------+
|      1 | D1_HS_308_ALM | 2020-02-10 11:55:00 | 0      |
|      2 | D1_HS_308_ALM | 2020-02-10 11:51:00 | 0      |
|      3 | D1_HS_308_ALM | 2020-02-10 11:49:00 | NULL   |
|      4 | D1_HS_308_ALM | 2020-02-10 11:46:00 | 1      |
|      5 | D1_HS_308_ALM | 2020-02-10 08:02:00 | 0      |
|      6 | D1_HS_308_ALM | 2020-02-10 08:02:00 | NULL   |
|      7 | D1_HS_308_ALM | 2020-02-10 08:02:00 | 0      |
|      8 | D1_HS_308_ALM | 2020-02-10 07:56:00 | 1      |
|      9 | D1_HS_308_ALM | 2020-02-10 07:51:00 | 1      |
|     10 | D1_HS_308_ALM | 2020-02-10 07:50:00 | 0      |
+--------+---------------+---------------------+--------+

此数据应return第 9 行-->7 转换为 11 分钟，第 4-->2 行转换为 5 分钟；这个名字总共 16 分钟。

当无法保证下一行具有正确的值更改时，我不确定如何完成此操作 - 有时会在几行或许多行之后。

Answer 1

DECLARE @myTable TABLE
(
    RowNum INT,
    Name VARCHAR(20),
    [Timestamp] DATETIME,
    Value INT
);

INSERT INTO @myTable
(
    RowNum,
    Name,
    [Timestamp],
    Value
)
VALUES
(1, 'D1_HS_308_ALM', '2020-02-10 11:55:00', 0),
(2, 'D1_HS_308_ALM', '2020-02-10 11:51:00', 0),
(3, 'D1_HS_308_ALM', '2020-02-10 11:49:00', NULL),
(4, 'D1_HS_308_ALM', '2020-02-10 11:46:00', 1),
(5, 'D1_HS_308_ALM', '2020-02-10 08:02:00', 0),
(6, 'D1_HS_308_ALM', '2020-02-10 08:02:00', NULL),
(7, 'D1_HS_308_ALM', '2020-02-10 08:02:00', 0),
(8, 'D1_HS_308_ALM', '2020-02-10 07:56:00', 1),
(9, 'D1_HS_308_ALM', '2020-02-10 07:51:00', 1),
(10, 'D1_HS_308_ALM', '2020-02-10 07:50:00', 0);

SELECT *,
       DATEDIFF(MINUTE, tStart, tEnd) AS duration
FROM
(
    SELECT t1.Name,
           MIN(t1.RowNum) AS rStart,
           MIN(t1.Timestamp) AS tStart,
           t.rNo AS rEnd,
           t.tEnd
    FROM @myTable t1
        OUTER APPLY
    (
        SELECT TOP (1)
               t2.RowNum,
               t2.Timestamp
        FROM @myTable t2
        WHERE t1.Name = t2.Name
              AND t2.Timestamp > t1.Timestamp
              AND t2.Value = 0
        ORDER BY t2.Timestamp
    ) t(rNo, tEnd)
    WHERE t1.Value = 1
    GROUP BY t1.Name,
             t.rNo,
             t.tEnd
) tmp;

更新：

SELECT Name,
       Sum(DATEDIFF(MINUTE, tStart, tEnd)) AS duration
FROM
(
    SELECT t1.Name,
           MIN(t1.Timestamp) AS tStart,
           t.tEnd
    FROM @myTable t1
        OUTER APPLY
    (
        SELECT TOP (1)
               t2.Timestamp
        FROM @myTable t2
        WHERE t1.Name = t2.Name
              AND t2.Timestamp > t1.Timestamp
              AND t2.Value = 0
        ORDER BY t2.Timestamp
    ) t(tEnd)
    WHERE t1.Value = 1
    GROUP BY t1.Name,
             t.tEnd
) tmp
group by name;

Answer 2

刚刚根据您的需要修改了 Cetin 的 select 查询：

DECLARE @myTable TABLE
(
    RowNum INT,
    Name VARCHAR(20),
    [Timestamp] DATETIME,
    Value INT
);

INSERT INTO @myTable
(
    RowNum,
    Name,
    [Timestamp],
    Value
)
VALUES
(1, 'D1_HS_308_ALM', '2020-02-10 11:55:00', 0),
(2, 'D1_HS_308_ALM', '2020-02-10 11:51:00', 0),
(3, 'D1_HS_308_ALM', '2020-02-10 11:49:00', NULL),
(4, 'D1_HS_308_ALM', '2020-02-10 11:46:00', 1),
(5, 'D1_HS_308_ALM', '2020-02-10 08:02:00', 0),
(6, 'D1_HS_308_ALM', '2020-02-10 08:02:00', NULL),
(7, 'D1_HS_308_ALM', '2020-02-10 08:02:00', 0),
(8, 'D1_HS_308_ALM', '2020-02-10 07:56:00', 1),
(9, 'D1_HS_308_ALM', '2020-02-10 07:51:00', 1),
(10, 'D1_HS_308_ALM', '2020-02-10 07:50:00', 0);


SELECT tmp.Name,
       SUM(DATEDIFF(MINUTE, tStart, tEnd)) AS duration
FROM
(
    SELECT t1.Name,
           --MIN(t1.RowNum) AS rStart,
           MIN(t1.Timestamp) AS tStart,
           --t.rNo AS rEnd,
           t.tEnd
    FROM @myTable t1
        OUTER APPLY
    (
        SELECT TOP (1)
               --t2.RowNum,
               t2.Timestamp
        FROM @myTable t2
        WHERE t1.Name = t2.Name
              AND t2.Timestamp > t1.Timestamp
              AND t2.Value = 0
        ORDER BY t2.Timestamp
    --) t(rNo, tEnd)
    ) t(tEnd)
    WHERE t1.Value = 1
    GROUP BY t1.Name,
             --t.rNo,
             t.tEnd
) tmp
GROUP BY tmp.Name;

Answer 3

您可以使用 window 个函数：

min() 有条件地获取值 0 的下一个时间戳。
lag() 查看之前的值。

然后向下过滤到从 0 到 1 的过渡并进行一些日期计算：

select t.*,
       datediff(seconds, timestamp, next_ts_0) as duration
from (select t.*,
             min(case when value = 0 then timestamp end) over (partition by name order by timestamp desc) as next_ts_0,
             lag(value) over (partition by name order by timestamp) as prev_value
      from t.*
     ) t
where (prev_value = 0 or prev_value is null) and value = 1

如何获得按名称分组的时差持续时间总计以及价值何时以某种方式变化？

How to get time difference Duration totals grouped by Name and when Value changes in certain way?

sql

sql-server

gaps-and-islands