从电子邮件中提取文本后，空格替换为 =20

Question

我尝试使用 python 中的电子邮件和 imaplib 模块获取收到的 gmail 的文本。用utf-8解码后，得到报文的payload后，所有的空格还是替换成=20。我可以使用另一个解码步骤来解决这个问题吗？

代码如下：（我从 youtube 教程中得到的 - https://youtu.be/Jt8LizzxkPU）

``

import email
import imaplib



username = "abc"
password = "123"

mail = imaplib.IMAP4_SSL("imap.gmail.com")
mail.login(username,password)

mail.select("inbox")

result, data = mail.uid("search", None,"ALL")

inbox_item_list = data[0].split()

for item in inbox_item_list:
    #most_recent = inbox_item_list[-1]
    #oldest = inbox_item_list[0]

    result2, email_data = mail.uid('fetch',item,'(RFC822)') 

    raw_email = email_data[0][1].decode("utf-8")

    email_message = email.message_from_string(raw_email)

    to_ = email_message['To']
    from_ = email_message['From']
    subject_ = email_message['Subject']

    counter = 1
    for part in email_message.walk():
        if part.get_content_maintype() == "multipart":
            continue
        filename = part.get_filename()
        if not filename:
            ext = ".html"
            filename = "msg-part-%08d%s" %(counter, ext)
        counter += 1   

    #save file
    content_type = part.get_content_type()
    print(subject_)
    print (content_type)
    if "plain" in content_type:
        print(part.get_payload())
    elif "html" in content_type:
        print("do some beautiful soup")
    else:
        print(content_type)

``

Answer 1

这是一个完整的代码示例，说明如何解码一封简单的电子邮件（包含文字 =20 以及应由 space 替换的 =20 序列） :

#!/usr/bin/env python3
import email.policy

email_text = """Subject: =?UTF-8?B?dGVzdCDwn5OnID0yMA==?=
Content-Type: text/plain; charset="UTF-8"
Content-Transfer-Encoding: quoted-printable

loooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo=
oooooooooooooooooooooooooooooong=20word
=3D20
^ line starts with =3D20
emoji: <=F0=9F=93=A7>"""
msg = email.message_from_string(
    email_text, policy=email.policy.default
)
print("Subject: <{subject}>".format_map(msg))
assert not msg.is_multipart()
print(msg.get_content())

输出

Subject: <test  =20>
loooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooong word
=20
^ line starts with =20
emoji: <>

msg.walk()、part.get_payload(decode=True)可以用来遍历更复杂的EmailMessage对象。参见 email Examples。

Answer 2

尝试import quopri，然后当你得到邮件正文的内容（或者任何里面有=20s的文本），你可以使用quopri.decodestring()

我是这样做的

quopri.decodestring(part.get_payload())

但请记住，如果您非常明确地想要从 quoted-printable 解码，请记住这是正确的。通常我会说@jfs 的答案更简洁。

从电子邮件中提取文本后，空格替换为 =20

Spaces replaced by =20 after extracting text from email

python

email

imap

imaplib

python-3.x

输出