Swift 解析 Google 搜索 API 文本文件

Question

我正在尝试解析 Google 在 http://suggestqueries.google.com/complete/search?client=firefox&q=YOURQUERY 的搜索自动完成端点的结果，但它返回的是一个没有键的文本文件。

这是一个示例输出：

["YOURQUERY",["yourquery","yourquery dou","yourquery s.r.o","yourquery отзывы","yourquery львів","yourquery s.r.o. львів"]]

这是我的代码：

let baseURL = "http://suggestqueries.google.com/complete/search?client=firefox&q="

var searchResults: [String] = []

func returnResults(searchTerm: String, completion: @escaping ([String?], Error?) -> Void) {
    let finalUrl = URL(string: baseURL + searchTerm)

    // 3. choose method to transmit and configure to do so
    var request = URLRequest(url: finalUrl!)
    request.httpMethod = "GET"

    // 4. request data
    URLSession.shared.dataTask(with: request) { (data, _, error) in
        // check for errors and data
        if let error = error {
            print("There was an error requesting data")
            return completion([], error)
        }
        guard let data = data else {
            print("There was an error getting data.", error)
            return completion([], NSError())
        }

        // if we got our data back, we need to decode it to match our model object
        let jsonDecoder = JSONDecoder()

        do {
            // 1. decode results into array
            let results = try jsonDecoder.decode([String].self, from: data)

            // 2. set search results var equal to our decoded results array
            self.searchResults = results

            completion(results, nil)
        } catch {
            print("There was an error decoding data.", error)
            completion([], error)
        }}.resume()
}

我收到解码错误：

There was an error decoding data. typeMismatch(Swift.String, Swift.DecodingError.Context(codingPath: [_JSONKey(stringValue: "Index 1", intValue: 1)], debugDescription: "Expected to decode String but found an array instead.", underlyingError: nil))

你会如何正确解码？

Answer 1

你的问题是返回的 JSON 是一个 Any 的数组。第一个元素是 String，第二个是字符串数组 [String]。由于 Any 不符合 Decodable 因此使用 JSONSerialization 方法会更容易

class func jsonObject(with data: Data, options opt: JSONSerialization.ReadingOptions = []) throws -> Any

将结果从 Any 转换为 [Any] 并将最后一个元素转换为字符串数组 [String].

let results = try (JSONSerialization.jsonObject(with: data) as? [Any])?.last as? [String] ?? []
print(results)

这将打印

"["yourquery", "yourquery dou", "yourquery s.r.o", "yourquery отзывы", "yourquery львів", "yourquery s.r.o. львів"]\n"

Swift 解析 Google 搜索 API 文本文件

Swift Parse Google Search API Text File

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nsurlsession

urlsession