如何在 Azure 数据资源管理器中将自定义 key/value 对字符串解析为 JSON 对象？

Question

我需要将一串属性解析为 JSON 对象。这是输入格式：

"var1=[val1] & var2=[val2] & var3=[val3] & var4=[val4]"

所需的输出：

{
   "var1": "val1",
   "var2": "val2",
   "var3": "val3",
   "var4": "val4"
}

我有答案，看下面...

Answer 1

Thanks Ziad Hammoud for providing this cool workaround!

print str = "var1=[val1] & var2=[val2] & var3=[val3] & var4=[val4]"
| extend str = replace("\] & ", "&", replace("=\[", "=", str))
| project Properties = parse_urlquery(str)['Query Parameters']
| where Properties.var2== "val2"

Answer 2

另一种方法是使用 extract_all()，然后 'converting' 使用 pack() 和 make_bag() 将数组属性坏：

print str = "var1=[val1] & var2=[val2] & var3=[val3] & var4=[val4]"
| project Properties = extract_all(@"(?P<key>\w+)?=\[(?P<value>.*?)\]", dynamic(["key","value"]), str)
| mv-apply Properties on (
    summarize make_bag(pack(tostring(Properties[0]), Properties[1]))
)

如何在 Azure 数据资源管理器中将自定义 key/value 对字符串解析为 JSON 对象？

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