Listview 中的 UWP C# Togglesswitch - 单击 Togglesswitch 时如何获取行的项目

Question

所以我在 Toggleswitch 上有这个 Listview。我想要做的是触发像 ItemClick="Event_Overview_Teams_ItemClick" 这样的事件但与 Toggled="TeamPresent_Toggled" 并处理点击行的 TeamID 等项目。

<ListView x:Name="Event_Overview_Teams" HorizontalAlignment="Center" Width="1787" Margin="0,48,0,10" IsItemClickEnabled="True" ItemClick="Event_Overview_Teams_ItemClick" SelectionMode="None">
                        <ListView.ItemTemplate>
                            <DataTemplate>
                                <Grid Width="900">
                                    <Grid.ColumnDefinitions>
                                        <ColumnDefinition Width="*" />
                                        <ColumnDefinition Width="*" />
                                        <ColumnDefinition Width="*" />
                                        <ColumnDefinition Width="*" />
                                        <ColumnDefinition Width="*" />
                                        <ColumnDefinition Width="*" />
                                        <ColumnDefinition Width="*" />
                                    </Grid.ColumnDefinitions>
                                    <TextBlock x:Name="TeamName" Grid.Column="0" Text="{Binding TeamName}" TextWrapping="Wrap" />
                                    <TextBlock x:Name="TeamID"   Grid.Column="1" Text="{Binding TeamID}" TextWrapping="Wrap" />
                                    <TextBlock x:Name="TeamNumber" Grid.Column="2" Text="{Binding TeamNumber}" TextWrapping="Wrap" />
                                    <TextBlock x:Name="TeamClass" Grid.Column="3" Text="{Binding TeamClass}" TextWrapping="Wrap" />
                                    <TextBlock x:Name="DeliverTime" Grid.Column="4" Text="{Binding DeliverTime}" TextWrapping="Wrap" />
                                    <!--<TextBlock x:Name="TeamPresent" Grid.Column="5" Text="{Binding TeamPresent}" TextWrapping="Wrap" />-->
                                    <ToggleSwitch x:Name="TeamPresent" Grid.Column="5" IsOn="{Binding TeamPresent}" Toggled="TeamPresent_Toggled"/>
                                </Grid>
                            </DataTemplate>
                        </ListView.ItemTemplate>
                    </ListView>

非常感谢您

Answer 1

当你触发TeamPresent_Toggled事件时，你可以通过获取DataContext[=15=获取当前item绑定的viewmodel ] 的拨动开关。然后从您获得的视图模型中更改属性（例如 TeamID）。

private void TeamPresent_Toggled(object sender, RoutedEventArgs e) { var toggle = (ToggleSwitch)sender; var dataContext = toggle.DataContext; MyViewModel dataItem = (MyViewModel)dataContext; dataItem.TeamID = "MyNewTeamId"; ...... }

Listview 中的 UWP C# Togglesswitch - 单击 Togglesswitch 时如何获取行的项目

UWP C# Toggleswitch inside Listview - How to get items of Row when clicked on Toggleswitch

c#

listview

toggleswitch

uwp