将重叠列表 data.frames 转换为单个列表 data.frame

Question

我在列表中有来自多个队列的一些人口信息。每个群组涵盖重叠的时间段。数据如下所示：

> raw.data
$`1`
  Year     Pop
1 1920 1927433
2 1921 1914551
3 1922 1900776

$`2`
  Year     Pop
1 1921 1915576
2 1922 1902075
3 1923 1887613

$`3`
  Year     Pop
1 1922 1902111
2 1923 1887862
3 1924 1872695

我想将其转换为单个数据框，其中列名是年份，对角线是人口数据。输出应如下所示：

> resulting.data
     1920    1921    1922    1923    1924
1 1927433 1915576 1902111      NA      NA
2      NA 1914551 1902075 1887862      NA
3      NA      NA 1900776 1887613 1872695

您可以在下面找到输入和所需输出的示例数据：

raw.data <- structure(list(`1` = structure(list(Year = 1920:1922, Pop = c(1927433L, 1914551L, 1900776L)), .Names = c("Year", "Pop"), row.names = c(NA, 3L), class = "data.frame"), `2` = structure(list(Year = 1921:1923, Pop = c(1915576L, 1902075L, 1887613L)), .Names = c("Year", "Pop"), row.names = c(NA, 3L), class = "data.frame"), `3` = structure(list(Year = 1922:1924, Pop = c(1902111L, 1887862L, 1872695L)), .Names = c("Year", "Pop"), row.names = c(NA, 3L), class = "data.frame")), .Names = c("1", "2", "3"))
resulting.data <- structure(list(X1920 = c(1927433, NA, NA), X1921 = c(1915576, 1914551, NA), X1922 = c(1902111, 1902075, 1900776), X1923 = c(NA, 1887862, 1887613), X1924 = c(NA, NA, 1872695)), .Names = c("X1920", "X1921", "X1922", "X1923", "X1924"), row.names = c(NA, -3L), class = "data.frame")

我查看了，它提供了一个类似的问题，但我未能根据自己的需要调整它。我还尝试使用 plyr 尝试先获取对角线，然后将它们组合起来，但我不确定如何进行组合。

Answer 1

使用 do.call() 和 rbind() 将数据转换为单个数据帧，然后 reshape2::dcast() 进行整形：

dat <- do.call(rbind, raw.data)
dat$obs <- gsub(".*?\.", "", row.names(dat))

library(reshape2)
dcast(dat, obs ~ Year, fun.aggregate = sum, value.var = "Pop")

     obs    1920    1921    1922    1923    1924
1   1 1927433 1915576 1902111       0       0
2   2       0 1914551 1902075 1887862       0
3   3       0       0 1900776 1887613 1872695

将重叠列表 data.frames 转换为单个列表 data.frame

Convert list of overlapping data.frames into single data.frame

r

dataframe

plyr