我如何找到特定数量的单词的出现

Question

大家好我有一个小问题假设我有一个字符串

"Hello My name is XYZ"

现在我知道我可以找到单词的长度，因为 "Hello" 有 5 个字符，"My" 有 2 个字符。通过使用以下代码

$text = file_get_contents('text.txt'); // $text = 'Hello my name is XYZ';
$words = str_word_count($text, 1);
$wordsLength = array_map(
function($word) { return mb_strlen($word, 'UTF-8'); },
$words
);

var_dump(array_combine($words, $wordsLength));

但是如果我想找到长度为1的单词个数怎么办？长度为2的单词个数为2个。长度为3的单词个数为1个等等，直到长度为10个

注意-我正在考虑单词长度，直到有一个 space 假设数据中有一个日期，如 20.04.2016，所以它应该告诉我数字是长度为 10 的单词是 1。

还有一件事，我如何找到字符串中单词的平均长度。提前谢谢你

Answer 1

如果您在 $wordsLength 数组上使用 array_count_values()，它将给出字符串长度的计数。如果您使用此模板数组（使用 array_fill() 创建），其中元素为 1-10，值为 0。您将获得所有字数的列表...

$counts = array_replace(array_fill(1, 9, 0), 
             array_count_values($wordsLength));

会给...

Array
(
    [1] => 0
    [2] => 2
    [3] => 1
    [4] => 1
    [5] => 1
    [6] => 0
    [7] => 0
    [8] => 0
    [9] => 0
)

Answer 2

你好试试这个它适用于日期和特殊字符，表情符号

$text = 'Hello 20.04.2016   my   faceface  is XYZ';

$words =preg_split('/\s+/', $text);

$wordsLength = array_map(
function($word) { return mb_strlen($word, 'UTF-8'); }  ,$words);

print_r($words);

//Get Average word Length
$avg=round(array_sum($wordsLength)/count($words),1);
//print Avg
print($avg);

?>

Answer 3

(Demo)

$text = '    Hello 20.04.2016   my   incredibleness faceface  is XYZ    ';

生成连续可见字符数组

$words = preg_split('/\s+/', $text, 0, PREG_SPLIT_NO_EMPTY);
array (
  0 => 'Hello',
  1 => '20.04.2016',
  2 => '',
  3 => 'my',
  4 => 'incredibleness',
  5 => 'faceface',
  6 => 'is',
  7 => 'XYZ',
)

用多字节长度替换可见字符串注意更简单的语法

$wordsLength = array_map('mb_strlen', $words);
array (
  0 => 5,
  1 => 10,
  2 => 1,
  3 => 2,
  4 => 14,
  5 => 9,
  6 => 2,
  7 => 3,
)

分组并计算长度

$lengthCounts = array_count_values($wordsLength);
array (
  5 => 1,
  10 => 1,
  1 => 1,
  2 => 2,
  14 => 1,
  9 => 1,
  3 => 1,
)

建立一个默认数组，因为$lengthCounts可能有空缺

$defaultCounts = array_fill_keys(range(1,10), 0);
array (
  1 => 0,
  2 => 0,
  3 => 0,
  4 => 0,
  5 => 0,
  6 => 0,
  7 => 0,
  8 => 0,
  9 => 0,
  10 => 0,
)

过滤计数以移除 elements/counts 超出范围的

$filteredCounts = array_intersect_key($lengthCounts, $defaultCounts);
array (
  5 => 1,
  10 => 1,
  1 => 1,
  2 => 2,
  9 => 1,
  3 => 1,
)

用找到的计数覆盖默认值以防止输出中出现间隙

$gaplessCounts = array_replace($defaultCounts, $filteredCounts);
array (
  1 => 1,
  2 => 2,
  3 => 1,
  4 => 0,
  5 => 1,
  6 => 0,
  7 => 0,
  8 => 0,
  9 => 1,
  10 => 1,
)

我如何找到特定数量的单词的出现

How do i find the occurence of words of particular number

php

string

word-count