如何描述继承class？

Question

我有一个 Base 和许多 (1..N) 派生类这样的：

class Base {
public:
  virtual void OnMouseMove(int x, int y) = 0;
}

class Derived_1: public Base {
public:
  void OnMouseMove(int x, int y) override;
}

class Derived_2: public Base {
public:
  void OnMouseMove(int x, int y) override;
}

void Derived_1::OnMouseMove(int x, int y) {actions 1};
void Derived_2::OnMouseMove(int x, int y) {actions 2};

所有派生的类具有 相同的定义 但不同 OnMouseMove() 函数。我不喜欢程序的外观，因为我必须在头文件中编写所有相同的派生函数，只是名称不同 Derived_1、Derived_2.

有没有可能把程序写得更短一些？我需要这样的东西：

class Derived: public Base {
public:
  void OnMouseMove(int x, int y) override;
}

class Derived_1 : public Derived{};
class Derived_2 : public Derived{};

void Derived_1::OnMouseMove(int x, int y) {actions 1};
void Derived_2::OnMouseMove(int x, int y) {actions 1};

Answer 1

在这种情况下使用模板怎么样：

class Base {
public:
  virtual void OnMouseMove(int x, int y) = 0;
};  

template < int N>
class Derived: public Base {
public:
  void OnMouseMove(int x, int y) override;
};

template<> void Derived<1>::OnMouseMove(int x, int y) {std::cout<< "1"<< std::endl;}
template<> void Derived<2>::OnMouseMove(int x, int y) {std::cout<< "2"<< std::endl;}

int main()
{
    Base* ptr1 = new Derived<1>;
    Base* ptr2 = new Derived<2>;

    ptr1->OnMouseMove(5,6);
    ptr2->OnMouseMove(5,6);
}

如何描述继承class？

How to describe the inherited class?

c++

templates

derived-class

base-class