比较 vba excel 中的两个字符串
Compare two strings in vba excel
我需要将"Chef"列的每个单元格与"nom"列的每个单元格进行比较,以便找到正确的"matricule"并将其存储在[=25]中=],
我试过这个 VBA 代码:
Sub compare()
Dim p As Integer
Dim q As Integer
Dim Nom As String
Dim Nomchercher As String
Dim Matr As String
p = 0
q = 0
For j = 1 To 10
p = p + 1
Cells.Find("Chef").Select
ActiveCell.Range("a1").Offset(p, 0).Activate
ActiveCell.Select
AdresseTexte1 = ActiveCell.Address(0, 0)
Nomchercher = Range(AdresseTexte1)
For i = 1 To 10
q = q + 1
Cells.Find("Nom").Select
ActiveCell.Range("a1").Offset(q, 0).Activate
AdresseTexte2 = ActiveCell.Address(0, 0)
Nom = UCase(Range(AdresseTexte2))
Cells.Find("Matricule").Select
ActiveCell.Range("a1").Offset(q, 0).Activate
AdresseTexte3 = ActiveCell.Address(0, 0)
Matr = UCase(Range(AdresseTexte3))
Cells.Find("Matt").Select
ActiveCell.Range("a1").Offset(p, 0).Activate
Temps = InStr(1, UCase(Nom), UCase(Nomchercher), vbTextCompare)
If Temps <> 0 Then
ActiveCell.Value = Matr
End If
Next i
q = 0
Next j
End Sub
但它给了我这个结果:
我不知道为什么显示“48”,有帮助吗?
问题出在 InStr
函数 -> https://msdn.microsoft.com/en-us/library/8460tsh1%28v=vs.90%29.aspx
Temps = InStr(1, UCase(Nom), UCase(Nomchercher), vbTextCompare)
您在 UCase(Nom)
中搜索 UCase(Nomchercher)
您总是在 Nomchercher
列的所有数据中找到 Nom = ""
这样效果会更好:
Temps = InStr(1, UCase(Nomchercher), UCase(Nom), vbTextCompare)
编辑:(比较快)
Sub FasterCompare()
Dim ColMatricule As Integer
Dim ColNom As Integer
Dim ColChef As Integer
Dim ColMatt As Integer
Dim LastRow As Long
ScreenUpdating = False
'find column name
ColMatricule = Cells.Find("Matricule").Column
ColNom = Cells.Find("Nom").Column
ColChef = Cells.Find("Chef").Column
ColMatt = Cells.Find("matt").Column
'find last row of data
LastRow = Cells.Find("*", searchorder:=xlByRows, searchdirection:=xlPrevious).Row
For j = 2 To LastRow 'chef
If Cells(j, ColChef) <> vbNullString Then 'if chef is null then dont search nom
For i = 2 To LastRow 'nom
If Cells(j, ColChef) = Cells(i, ColNom) Then
Cells(j, ColMatt) = Cells(i, ColMatricule)
Exit For
End If
Next i
End If
Next j
ScreenUpdating = True
End Sub
我需要将"Chef"列的每个单元格与"nom"列的每个单元格进行比较,以便找到正确的"matricule"并将其存储在[=25]中=], 我试过这个 VBA 代码:
Sub compare()
Dim p As Integer
Dim q As Integer
Dim Nom As String
Dim Nomchercher As String
Dim Matr As String
p = 0
q = 0
For j = 1 To 10
p = p + 1
Cells.Find("Chef").Select
ActiveCell.Range("a1").Offset(p, 0).Activate
ActiveCell.Select
AdresseTexte1 = ActiveCell.Address(0, 0)
Nomchercher = Range(AdresseTexte1)
For i = 1 To 10
q = q + 1
Cells.Find("Nom").Select
ActiveCell.Range("a1").Offset(q, 0).Activate
AdresseTexte2 = ActiveCell.Address(0, 0)
Nom = UCase(Range(AdresseTexte2))
Cells.Find("Matricule").Select
ActiveCell.Range("a1").Offset(q, 0).Activate
AdresseTexte3 = ActiveCell.Address(0, 0)
Matr = UCase(Range(AdresseTexte3))
Cells.Find("Matt").Select
ActiveCell.Range("a1").Offset(p, 0).Activate
Temps = InStr(1, UCase(Nom), UCase(Nomchercher), vbTextCompare)
If Temps <> 0 Then
ActiveCell.Value = Matr
End If
Next i
q = 0
Next j
End Sub
但它给了我这个结果:
我不知道为什么显示“48”,有帮助吗?
问题出在 InStr
函数 -> https://msdn.microsoft.com/en-us/library/8460tsh1%28v=vs.90%29.aspx
Temps = InStr(1, UCase(Nom), UCase(Nomchercher), vbTextCompare)
您在 UCase(Nom)
UCase(Nomchercher)
您总是在 Nomchercher
Nom = ""
这样效果会更好:
Temps = InStr(1, UCase(Nomchercher), UCase(Nom), vbTextCompare)
编辑:(比较快)
Sub FasterCompare()
Dim ColMatricule As Integer
Dim ColNom As Integer
Dim ColChef As Integer
Dim ColMatt As Integer
Dim LastRow As Long
ScreenUpdating = False
'find column name
ColMatricule = Cells.Find("Matricule").Column
ColNom = Cells.Find("Nom").Column
ColChef = Cells.Find("Chef").Column
ColMatt = Cells.Find("matt").Column
'find last row of data
LastRow = Cells.Find("*", searchorder:=xlByRows, searchdirection:=xlPrevious).Row
For j = 2 To LastRow 'chef
If Cells(j, ColChef) <> vbNullString Then 'if chef is null then dont search nom
For i = 2 To LastRow 'nom
If Cells(j, ColChef) = Cells(i, ColNom) Then
Cells(j, ColMatt) = Cells(i, ColMatricule)
Exit For
End If
Next i
End If
Next j
ScreenUpdating = True
End Sub