使用 Ansible 删除文件中字符串前的每一行

Question

我有以下文件：

Scheduled jobs
Locale LANG set to the following: "en"
CONMAN:AWSBHU611W Conman could not initialize the HTTP or HTTPS connection.
Workstation Job Stream SchedTime Job State Pr Start Elapse ReturnCode Dependencies

HCPRODNWA #NW_HC_CA_BKP1 0106 02/13 **************************************** HOLD 10(02/13) (03:22)
NW_HC_CA_PREBKUP1B HOLD 10(02/13)(00:01)
NW_HC_CA_SANREPLICATION HOLD 10(02/13)(00:05)ΩNW_HC_CA_PREBKUP1B
NW_HC_CA_PPBACKUP HOLD 10(02/13)(03:17)
NW_HC_CA_SANREPLICATION
NW_HC_CA_GOLDCOPY HOLD 10(02/13)(00:01)
NW_HC_CA_SANREPLICATION

我想删除以 'Workstation Job...'

开头的行之前的所有行

我的ansible代码是：

- name: Extract job details
  replace:
    path: /tmp/tws_jobs
    after: '(^Scheduled)'
    before: '(^Workstation)'
    regexp: '^(.*)$'
    replace: ''

但我无法获得所需的输出。相反，我收到以下消息：

"msg": "Pattern for before/after params did not match the given file: (^Scheduled)(?P<subsection>.*?)(^Workstation)"

Answer 1

尝试另一种方法：blockinfile：

- name: Extract job details
  blockinfile:
    marker_begin: '^Scheduled'
    marker_end: '^Workstation'

Answer 2

Q: "Pattern for before/after params did not match the given file ..."

A：before 和 after 模式都不匹配文件中的任何行。正确的模式应该是

    after: '^Scheduled(.*)$'
    before: '^Workstation(.*)$'

但是这些模式也不起作用，可能是因为未解决的问题 Replace module before/after still broken #47917。

可以在一个简化的示例中测试各种模式

shell> cat test.txt
aaa
bbb
ccc
ddd
eee

任务

   - replace:
        path: test.txt
        after: 'bbb'
        before: 'ddd'
        regexp: '^(.*)$'
        replace: ''

按预期工作

shell> cat test.txt
aaa
bbb

ddd
eee

但都不是

   - replace:
        path: test.txt
        after: '^bb'
        before: '^dd'
        regexp: '^(.*)$'
        replace: ''

也不

   - replace:
        path: test.txt
        after: '^bb(.*)$'
        before: '^dd(.*)$'
        regexp: '^(.*)$'
        replace: ''

更改文件中的任何内容

PLAY RECAP *************************************************************************
localhost: ok=1  changed=0  unreachable=0  failed=0  skipped=0  rescued=0  ignored=0

[1] https://github.com/ansible/ansible/issues/47917#issuecomment-686339762

使用 Ansible 删除文件中字符串前的每一行

Remove every line before a string in file using Ansible

regex

ansible

regexp-replace

ansible-bug