PHP: try-catch-finally 在循环中，在 catch 中继续

Question

好的，只是关于上面代码的技术问题：

foreach($x as $y){ // or even a simple for()
    try{
        a();
    } catch(\Exception $e){
        // just skip current iteration
        continue;
    } finally {
        c();
    }
}

因为 c() 在 finally 块中，它应该总是被执行，但是 continue 语句呢？
根据 documentation 它似乎使 finally 块被跳过。

那么，c()是否在a()抛出异常的情况下执行？

Answer 1

使用控制台很容易发现。输入

php -r 'foreach([1, 2] as $n){try {echo "\n", $n, "\n"; throw new \Exception();} catch (\Exception $e) {continue;} finally {echo "finally has been called";}}'

这是代码的单字符串表示

foreach ([1, 2] as $n) {
    try {
        echo "\n", $n, "\n";
        throw new \Exception();
    } catch (\Exception $e) {
        continue;
    } finally {
        echo "finally has been called";
    }
}

你会得到

1
finally has been called
2
finally has been called

PHP: try-catch-finally 在循环中，在 catch 中继续

PHP: try-catch-finally in loop with continue in catch

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