如何在没有 OOM 杀手的情况下发出 C++ 终止捕获

Question

我正在从一本书中学习异常，try/catch 并且 OS 应该终止以下程序。

书上说，消息 terminate called after throwing an instance of 'std::bad_alloc' 应该出现。但是没有。

我正在使用 Arch Linux 并且程序没有停止。它运行，填充 RAM 有点线性直到它不（大约 90%），处理器工作很多但没有冻结也没有终止。这是 Windows 的唯一用例，还是我如何在 Linux/maybe Unix 系统上重现错误？

    #include <iostream>
    #include <exception> //c++ exception

    int main()
    {
    int *feld;
    int loop = 1;

    for(;;) //infinite loop
    {
      std::cout << "Loop number: " << loop << '\n';
      try
      {
      feld = new int[10000];
      loop++;
      if (durchlauf == 100000) //since c++11
            std::terminate();
      }
      catch(...)
        {

        std::cout << "Error, Program done.\n";

        break;
        }
      }
    return 0;
    }

编辑：我发现我的 OOM 杀手无法正常使用 swap enabled/at all。但是c++有自己的终止进程调用 https://en.cppreference.com/w/cpp/error/terminate 它只是不会发出异常来打印出捕获线。有没有人提示发出捕获终止？

Answer 1

我found以下代码供您编写一些终止程序：希望对您有所帮助。

    #include <iostream>
    #include <stdexcept>

    struct A {
        int n;
        A(int n = 0): n(n) { std::cout << "A(" << n << ") constructed successfully\n"; }
        ~A() { std::cout << "A(" << n << ") destroyed\n"; }
    };

    int foo()
    {
        throw std::runtime_error("error");
    }

    struct B {
        A a1, a2, a3;
        B() try : a1(1), a2(foo()), a3(3) {
            std::cout << "B constructed successfully\n";
        } catch(...) {
            std::cout << "B::B() exiting with exception\n";
        }
        ~B() { std::cout << "B destroyed\n"; }
    };

    struct C : A, B {
        C() try {
            std::cout << "C::C() completed successfully\n";
        } catch(...) {
            std::cout << "C::C() exiting with exception\n";
        }
        ~C() { std::cout << "C destroyed\n"; }
    };

    int main () try
    {
        // creates the A base subobject
        // creates the a1 member of B
        // fails to create the a2 member of B
        // unwinding destroys the a1 member of B
        // unwinding destroys the A base subobject
        C c;
    } catch (const std::exception& e) {
        std::cout << "main() failed to create C with: " << e.what();
    }

Answer 2

只是为了在有人遇到相同问题时提供帮助 100000 次循环后编码抛出的异常：

    #include <iostream>
    #include <exception> //c++ exception

        int main()
        {
        int *feld;
        int loop = 1;

        for(;;) //infinite loop
        {

          std::cout << "Loop number: " << loop << '\n';
          try
          {
             feld = new int[10000];
             loop++;
             if (loop == 1e5)
                throw std::bad_alloc(); //has to be inside the try(){} scope
          }

          catch(...)
            {

            std::cout << "Error, Program done.\n";

            break;
            }
          }
        return 0;
        }

如何在没有 OOM 杀手的情况下发出 C++ 终止捕获

How to issue a c++ termination catch without a OOM killer

c++

linux

exception

archlinux