在 C++ 中用循环构建和生成一副纸牌
Structuring and generating a deck of cards with a loop in c++
它在 c++ 中
我的想法是对其进行设置,使其不断循环遍历所有卡片以不断获得不同的结果和答案,直到所有 52 张卡片都消失了我不知道它的确切位置我知道它
for(int i = 0; i < 5; i++)
{
cout << i << endl;
}
我不太确定如何设置数组如果我只是像字符串 {ace, one two} 等等那样设置..但是我有标记为 52 的数组,即使将它们全部输入它只有 13数字在 4 套花色中重复了 4 次,所以你会class 把它们分开吗?或者有什么用吗?
#include <iostream>
using namespace std;
class cardGame;
int main()
{
int bet;
int dealer[52] = { 13, 13, 13, 13 };
int player[52] = { 13, 13, 13, 13 };
int dealerCard1;
int dealerCard2;
int playerCard1;
int playerCard2;
int dealerTotal;
int playerTotal;
int shuffle;
cout << "This is My attempt at BlackJack" << endl;
cout << endl;
cin >> bet;
cout << "Player enter amount to bet: $ ";
cout << endl;
cin >> shuffle;
cardGame::playeer(playerCard1 + playerCard2 = playerTotal);
cardsGame.playerCard1 = 0;
cardsGame.playerCard2 = 0;
cardsGame.playerTotal = 0;
cout << "the First card is: " << cardsGame.playerCard1 = 0 << endl;
cout << "The second card is: " << cardsGame.playerCard = 0 << endl;
cout << "Your total is: " << cardsGame.playerTotal = 0 << endl;
cardGame::playeer(playerCard1 + playerCard2 = playerTotal);
if (playerCard1 + playerCard2 == 21)
{
cout << "WINNER WINNER CHICKEN DINNER!" << endl;
};
else (playerCard1 + playerCard2 > 21)
{
cout << "What a dissapointment you are to everyone!" << endl;
};
if (playerCard1 + playerCard2 > dealerTotal)
{
cout << "WINNER WINNER CHICKEN DINNER!" << endl;
};
else (playerCard1 + playerCard2 == dealerTotal)
{
cout << "What a dissapointment you are to everyone!"
}
cardGame::dealer(dealerCard1 + dealerCard2 = dealerTotal);
cardsGame.dealerCard1 = 0;
cardsGame.dealerCard2 = 0;
cardsGame.dealerTotal = 0;
cout << "the First card is: " << cardsGame.dealerCard1 = 0 << endl;
cout << "The second card is: " << cardsGame.dealerCard2 = 0 << endl;
cout << "Your total is: " << cardsGame.dealerTotal = 0 << endl;
cardGame::dealer(dealerCard1 + playerCard2 = playerTotal);
if (dealerCard1 + dealerCard2 == 21)
{
cout << "What a dissapointment you are to everyone!" << endl;
};
else (dealerCard1 + dealerCard2 > 21)
{
cout << "WINNER WINNER CHICKEN DINNER" << endl;
}
if (dealerCard1 + dealerCard2 > playerTotal)
{
cout << "What a dissapointment you are to everyone!" << cout endl:
};
else (dealerCard1 + dealerCard2 < playerTotal)
{
cout << "What a dissapointment you are to everyone!"
}
}
我不懂c++(或blackjack);但下面是一个 in Javascript 的示例,它说明了一些概念,可能会推动您朝着正确的方向前进。
就结构而言,您可能需要这样的东西:
// Set up your 'deck'
deck = {
hearts: [],
spades: [],
diamonds: [],
clubs: []
}
// The object 'deck' has four properties (hearts, spades...), each of which is an empty array.
// Use a loop to add your 'cards'
Object.keys(deck).forEach(suit => {
for (i = 1; i < 14; i++) {
deck[suit].push(i);
}
});
// For each property in the object 'deck', push ascending consecutive integers starting from the number 1 to each array, until the number 14 is reached.
这给你:
deck = {
hearts: [1,2,3,4,5,6,7,8,9,10,11,12,13],
spades: [1,2,3,4,5,6,7,8,9,10,11,12,13],
diamonds: [1,2,3,4,5,6,7,8,9,10,11,12,13],
clubs: [1,2,3,4,5,6,7,8,9,10,11,12,13]
}
它在 c++ 中
我的想法是对其进行设置,使其不断循环遍历所有卡片以不断获得不同的结果和答案,直到所有 52 张卡片都消失了我不知道它的确切位置我知道它
for(int i = 0; i < 5; i++)
{
cout << i << endl;
}
我不太确定如何设置数组如果我只是像字符串 {ace, one two} 等等那样设置..但是我有标记为 52 的数组,即使将它们全部输入它只有 13数字在 4 套花色中重复了 4 次,所以你会class 把它们分开吗?或者有什么用吗?
#include <iostream>
using namespace std;
class cardGame;
int main()
{
int bet;
int dealer[52] = { 13, 13, 13, 13 };
int player[52] = { 13, 13, 13, 13 };
int dealerCard1;
int dealerCard2;
int playerCard1;
int playerCard2;
int dealerTotal;
int playerTotal;
int shuffle;
cout << "This is My attempt at BlackJack" << endl;
cout << endl;
cin >> bet;
cout << "Player enter amount to bet: $ ";
cout << endl;
cin >> shuffle;
cardGame::playeer(playerCard1 + playerCard2 = playerTotal);
cardsGame.playerCard1 = 0;
cardsGame.playerCard2 = 0;
cardsGame.playerTotal = 0;
cout << "the First card is: " << cardsGame.playerCard1 = 0 << endl;
cout << "The second card is: " << cardsGame.playerCard = 0 << endl;
cout << "Your total is: " << cardsGame.playerTotal = 0 << endl;
cardGame::playeer(playerCard1 + playerCard2 = playerTotal);
if (playerCard1 + playerCard2 == 21)
{
cout << "WINNER WINNER CHICKEN DINNER!" << endl;
};
else (playerCard1 + playerCard2 > 21)
{
cout << "What a dissapointment you are to everyone!" << endl;
};
if (playerCard1 + playerCard2 > dealerTotal)
{
cout << "WINNER WINNER CHICKEN DINNER!" << endl;
};
else (playerCard1 + playerCard2 == dealerTotal)
{
cout << "What a dissapointment you are to everyone!"
}
cardGame::dealer(dealerCard1 + dealerCard2 = dealerTotal);
cardsGame.dealerCard1 = 0;
cardsGame.dealerCard2 = 0;
cardsGame.dealerTotal = 0;
cout << "the First card is: " << cardsGame.dealerCard1 = 0 << endl;
cout << "The second card is: " << cardsGame.dealerCard2 = 0 << endl;
cout << "Your total is: " << cardsGame.dealerTotal = 0 << endl;
cardGame::dealer(dealerCard1 + playerCard2 = playerTotal);
if (dealerCard1 + dealerCard2 == 21)
{
cout << "What a dissapointment you are to everyone!" << endl;
};
else (dealerCard1 + dealerCard2 > 21)
{
cout << "WINNER WINNER CHICKEN DINNER" << endl;
}
if (dealerCard1 + dealerCard2 > playerTotal)
{
cout << "What a dissapointment you are to everyone!" << cout endl:
};
else (dealerCard1 + dealerCard2 < playerTotal)
{
cout << "What a dissapointment you are to everyone!"
}
}
我不懂c++(或blackjack);但下面是一个 in Javascript 的示例,它说明了一些概念,可能会推动您朝着正确的方向前进。
就结构而言,您可能需要这样的东西:
// Set up your 'deck'
deck = {
hearts: [],
spades: [],
diamonds: [],
clubs: []
}
// The object 'deck' has four properties (hearts, spades...), each of which is an empty array.
// Use a loop to add your 'cards'
Object.keys(deck).forEach(suit => {
for (i = 1; i < 14; i++) {
deck[suit].push(i);
}
});
// For each property in the object 'deck', push ascending consecutive integers starting from the number 1 to each array, until the number 14 is reached.
这给你:
deck = {
hearts: [1,2,3,4,5,6,7,8,9,10,11,12,13],
spades: [1,2,3,4,5,6,7,8,9,10,11,12,13],
diamonds: [1,2,3,4,5,6,7,8,9,10,11,12,13],
clubs: [1,2,3,4,5,6,7,8,9,10,11,12,13]
}