如何在赛普拉斯测试中实现自定义命令

Question

我编写了一个自定义命令来从 window 获取身份验证令牌，如下所示

Cypress.Commands.add("getToken", AUTH => {
 return cy.window().then(window => window.localStorage.getItem(AUTH));
});

const authToken = JSON.parse(window.localStorage.getItem("AUTH")); 

authToken = returned the authtoken. I want to know how to make`enter code here` this as 
function/custom command so that the other t`enter code here`est could use this.

Answer 1

我建议这样：

describe('', () => {
  let tokens = {};

  it('', () => {
    cy
      .getToken('AUTH', ({ token }) => {
        Object.assign(tokens, { auth: token });
      })
      .request({
        headers: { "Content-Type": "application/json", Authorization: `Bearer ${tokens.auth}`, }
      })

  });
});

你还需要稍微改变一下getToken命令：

Cypress.Commands.add("getToken", (AUTH, cb) => {
 return cy.window().then(window => cb(window.localStorage.getItem(AUTH)));
});

如何在赛普拉斯测试中实现自定义命令

How to implement a custom command In Cypress test

cucumberjs

cypress