GuzzleHttp\\Exception\\ClientException: Client error: `POST resulted in a `400 Bad Request` response:\n{"@context":"\\/api\\/contexts

Question

我已经使用本教程 https://symfonycasts.com/screencast/api-platform 构建了一个 API 端点。我已经从 Web 界面测试了 API，它接受输入并存储数据。现在我正在尝试将数据从我的应用程序发送到端点。

 curl -X POST "https://myweblocation.app/api/emergencyvisits" -H "accept: application/ld+json" -H "Content-Type: application/json" -d "{\"externalpatientid\":\"<patient-id>\",\"externalsiteid\":\"<site-id>\",\"poscode\":20,\"dos\":\"2020-02-28T00:10:52.416Z\",\"vistreason\":\"chest hurting bad\"}"

我的代码是这样的：

    $client = new Client(['verify' => 'my/pem/location.pem' ]);
    $siteid = $GLOBALS['unique_installation_id'];

    $body = [
        'externalpatientid' => $uuid,
        'externalsiteid' => $siteid,
        'poscode' => $pos_code,
        'dos' => $date,
        'visitreason' => $reason
    ];

    $headers = [
    'content-type' => 'application/json',
        'accept' => 'application/ld+json'
    ];

    $request = new Request('POST', 'https://myweblocation.app/api/emergencyvisits', $headers, json_encode($body));

    $response = $client->send($request, ['timeout' => 2]);

如何让 Guzzle 以编程方式为服务器生成正确的 post？

Answer 1

首先，请不要 post 敏感数据，例如患者 ID、站点 ID 或您的申请 URL。

关于您的问题... 在您的 curl 命令中，您使用参数名称 vistreason 但在您的 Guzzle 请求中，您使用 visitreason.

我已经使用 Postman 对其进行了测试，它返回了 500 服务器错误，因为字段 vistreason 不能为空。

除此之外，我还使用 Guzzle (6.x) 进行了测试：

$client = new Client(['verify' => false]); // I deactivated ssl verification
$body = [
    'externalpatientid' => '<id from curl request>',
    'externalsiteid' => '<id from curl request>',
    'poscode' => 20,
    'dos' => '2020-02-28T00:10:52.416Z',
    'vistreason' => 'chest hurting bad'
];

$response = $client->request(
    'POST',
    '<your-server-api-url>',
    [
        'headers' => [
            'content-type' => 'application/json',
            'accept' => 'application/ld+json'
        ],
        'body' => json_encode($body),
    ]
);

var_dump(json_decode($response->getBody()->getContents()));
// Output seems to be a valid response with some data from the request.

可能是您的验证证书有问题。

注意：我还强烈建议以令牌的形式实施身份验证，以便与您的 API!

进行交互

GuzzleHttp\\Exception\\ClientException: Client error: `POST resulted in a `400 Bad Request` response:\n{"@context":"\\/api\\/contexts

GuzzleHttp\\Exception\\ClientException: Client error: `POST resulted in a `400 Bad Request` response:\n{"@context":"\\/api\\/contexts

php

api-platform.com

symfony5