运行 并行的 TaskEithers 数组,但如果 1 个或多个任务失败则继续
Running an array of TaskEithers in parallel, but continue if 1 or more task fails
我必须并行进行一组 IO 调用,如果成功则合并调用的内容。如果一个失败,其他的将按正常方式处理,但会出现错误消息。
我对如何实现这一点的思考过程:
Array<TE<E, A>> -> TE<E, Array<A>> -> TE<E, MergedA> -> [E, A]
我目前在做什么:
我目前正在对 TE 阵列进行测序,但链中的任何故障都会产生一个左侧。
pipe(
sequenceT(TE.taskEither)(arrayofTE), //TE<E,A>[] -> TE<E,A[]>
TE.map(mergeFn), //TE<E, A[]> -> TE<E, MergedA>
???
)
如何停止短路?
您可以将 T.task
而不是 TE.taskEither
传递给 sequence
/sequenceT
(docs):
Action: execute an array of tasks in parallel, collecting all failures and successes
TaskEither: array.sequence(T.task)(taskEithers) - same for sequenceT
sequence
: 运行 并行任务
import { pipeable as P, taskEither as TE, task as T, array as A, either as E } from "fp-ts";
const arrayofTE: TE.TaskEither<string, number>[] = [
TE.right(1),
TE.right(2),
TE.left("Oh shit")
];
const run = P.pipe(
// change to T.task instead of TE.taskEither here
A.array.sequence(T.task)(arrayofTE),
mergeFn
);
run(); // run side effect
// returns Promise<{"errors":["Oh shit"],"results":[1,2]}>
// whatever merged result you want to have; this one collects all errors and all results
declare function mergeFn(te: T.Task<E.Either<string, number>[]>): T.Task<Results>
type Results = { errors: string[]; results: number[] };
sequenceT
: 运行 并行不同类型的任务
import { apply as AP /* and others above */ } from "fp-ts";
// Here, TaskEither result can be number | boolean (success case), string on error
const arrayofTE = [TE.right(1), TE.right(true), TE.left("Oh shit")] as const;
const run = P.pipe(
AP.sequenceT(T.task)(...arrayofTE), // we use sequenceT here and pass T.task again
mergeFn
);
declare function mergeFn(a: T.Task<E.Either<string, number | boolean>[]>): T.Task<Results>
我必须并行进行一组 IO 调用,如果成功则合并调用的内容。如果一个失败,其他的将按正常方式处理,但会出现错误消息。
我对如何实现这一点的思考过程:
Array<TE<E, A>> -> TE<E, Array<A>> -> TE<E, MergedA> -> [E, A]
我目前在做什么:
我目前正在对 TE 阵列进行测序,但链中的任何故障都会产生一个左侧。
pipe(
sequenceT(TE.taskEither)(arrayofTE), //TE<E,A>[] -> TE<E,A[]>
TE.map(mergeFn), //TE<E, A[]> -> TE<E, MergedA>
???
)
如何停止短路?
您可以将 T.task
而不是 TE.taskEither
传递给 sequence
/sequenceT
(docs):
Action: execute an array of tasks in parallel, collecting all failures and successes
TaskEither: array.sequence(T.task)(taskEithers) - same for sequenceT
sequence
: 运行 并行任务
import { pipeable as P, taskEither as TE, task as T, array as A, either as E } from "fp-ts";
const arrayofTE: TE.TaskEither<string, number>[] = [
TE.right(1),
TE.right(2),
TE.left("Oh shit")
];
const run = P.pipe(
// change to T.task instead of TE.taskEither here
A.array.sequence(T.task)(arrayofTE),
mergeFn
);
run(); // run side effect
// returns Promise<{"errors":["Oh shit"],"results":[1,2]}>
// whatever merged result you want to have; this one collects all errors and all results
declare function mergeFn(te: T.Task<E.Either<string, number>[]>): T.Task<Results>
type Results = { errors: string[]; results: number[] };
sequenceT
: 运行 并行不同类型的任务
import { apply as AP /* and others above */ } from "fp-ts";
// Here, TaskEither result can be number | boolean (success case), string on error
const arrayofTE = [TE.right(1), TE.right(true), TE.left("Oh shit")] as const;
const run = P.pipe(
AP.sequenceT(T.task)(...arrayofTE), // we use sequenceT here and pass T.task again
mergeFn
);
declare function mergeFn(a: T.Task<E.Either<string, number | boolean>[]>): T.Task<Results>