我可以将闹钟更改为重复闹钟吗?
can i change an alarn to a repeating alarm?
我怎样才能将一个已经设置好的闹钟改为重复闹钟?
我用 AlarmManager
设置闹钟?
我的实际代码如下所示:
intent = new Intent(MainActivity.this, AlarmReceiverActivity.class);
pendingIntent = PendingIntent.getActivity(MainActivity.this, 2, intent, PendingIntent.FLAG_CANCEL_CURRENT);
am = (AlarmManager) getSystemService(ALARM_SERVICE);
am.setRepeating(AlarmManager.RTC_WAKEUP, time, intervall, pendingIntent);
感谢您的帮助,
弗洛里安
编辑:我用另一种方式解决了我的问题(每次都设置一个新闹钟),所以没有压力,但我仍然想知道这将如何工作
您已通过服务 class 完成了这项工作。
例如
在 Application's onCreate()
方法中,您必须像下面这样初始化 AlarmManager
。
long l = 60000;
try {
AlarmManager alarmManager = (AlarmManager) context.getSystemService(Context.ALARM_SERVICE);
Intent intent = new Intent(context, SyncBroadcastReceiver.class);
PendingIntent pendingIntent = PendingIntent.getBroadcast(context, SYNC_CALL_TO_SERVER_PENDING_INTENT,
intent, PendingIntent.FLAG_UPDATE_CURRENT);
alarmManager.setInexactRepeating(AlarmManager.RTC_WAKEUP, System.currentTimeMillis(), l, pendingIntent);
}catch (Exception e){
e.printStackTrace();
}
并且SyncBroadcastReceiver
喜欢,
public class SyncBroadcastReceiver extends BroadcastReceiver {
@Override
public void onReceive(Context context, Intent intent) {
try {
//comment to check crash
Intent intent1 = new Intent(context, ServiceClass.class);
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
context.startForegroundService(intent1);
} else {
context.startService(intent1);
}
} catch (Exception e){
e.printStackTrace();
}
}
}
和 ServiceClass 一样
public class ServiceClass extends Service {
@Override
public int onStartCommand(Intent intent, int flags, int startId) {
// hitNotification(); // what need to act like notification dialog
return START_NOT_STICKY;
}
}
我怎样才能将一个已经设置好的闹钟改为重复闹钟?
我用 AlarmManager
设置闹钟?
我的实际代码如下所示:
intent = new Intent(MainActivity.this, AlarmReceiverActivity.class);
pendingIntent = PendingIntent.getActivity(MainActivity.this, 2, intent, PendingIntent.FLAG_CANCEL_CURRENT);
am = (AlarmManager) getSystemService(ALARM_SERVICE);
am.setRepeating(AlarmManager.RTC_WAKEUP, time, intervall, pendingIntent);
感谢您的帮助,
弗洛里安
编辑:我用另一种方式解决了我的问题(每次都设置一个新闹钟),所以没有压力,但我仍然想知道这将如何工作
您已通过服务 class 完成了这项工作。
例如
在 Application's onCreate()
方法中,您必须像下面这样初始化 AlarmManager
。
long l = 60000;
try {
AlarmManager alarmManager = (AlarmManager) context.getSystemService(Context.ALARM_SERVICE);
Intent intent = new Intent(context, SyncBroadcastReceiver.class);
PendingIntent pendingIntent = PendingIntent.getBroadcast(context, SYNC_CALL_TO_SERVER_PENDING_INTENT,
intent, PendingIntent.FLAG_UPDATE_CURRENT);
alarmManager.setInexactRepeating(AlarmManager.RTC_WAKEUP, System.currentTimeMillis(), l, pendingIntent);
}catch (Exception e){
e.printStackTrace();
}
并且SyncBroadcastReceiver
喜欢,
public class SyncBroadcastReceiver extends BroadcastReceiver {
@Override
public void onReceive(Context context, Intent intent) {
try {
//comment to check crash
Intent intent1 = new Intent(context, ServiceClass.class);
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
context.startForegroundService(intent1);
} else {
context.startService(intent1);
}
} catch (Exception e){
e.printStackTrace();
}
}
}
和 ServiceClass 一样
public class ServiceClass extends Service {
@Override
public int onStartCommand(Intent intent, int flags, int startId) {
// hitNotification(); // what need to act like notification dialog
return START_NOT_STICKY;
}
}