Python 单击按钮时 PyQt5 终端命令执行问题
Python PyQt5 Terminal Command execution problem on a button click
我正在尝试创建一个应用程序,它可以在单击按钮时执行嵌入式终端命令。实际问题发生在我单击按钮但没有任何反应时。
我有两个脚本,一个有终端小部件,另一个有主 GUI。任何帮助,将不胜感激。
这是第一个脚本
import sys
from PyQt5 import QtCore, QtWidgets
class EmbTerminal(QtWidgets.QWidget):
def __init__(self, parent=None):
super(EmbTerminal, self).__init__(parent)
self._process = []
self.start_process('urxvt',['-embed', str(int(self.winId())),"-e","tmux"])
def start_process(self,prog,options):
child = QtCore.QProcess(self)
self._process.append(child)
child.start(prog,options)
def run_command(self, command = "ls" ):
program = "tmux"
options = []
options.extend(["send-keys"])
options.extend([command])
options.extend(["Enter"])
self.start_process(program, options)
这是第二个剧本
from PyQt5 import QtCore, QtGui, QtWidgets
class Ui_Dialog(object):
def setupUi(self, Dialog):
Dialog.setObjectName("Dialog")
Dialog.resize(745, 496)
self.tabWidget = QtWidgets.QTabWidget(Dialog)
self.tabWidget.setGeometry(QtCore.QRect(100, 190, 561, 261))
self.tabWidget.setObjectName("tabWidget")
self.tab = QtWidgets.QWidget()
self.tab.setObjectName("tab")
self.tabWidget.addTab(EmbTerminal(), "Terminal")
self.tab_2 = QtWidgets.QWidget()
self.tab_2.setObjectName("tab_2")
self.tabWidget.addTab(self.tab_2, "")
self.pushButton = QtWidgets.QPushButton(Dialog)
self.pushButton.setGeometry(QtCore.QRect(280, 70, 211, 71))
self.pushButton.setObjectName("pushButton")
self.retranslateUi(Dialog)
QtCore.QMetaObject.connectSlotsByName(Dialog)
self.pushButton.clicked.connect(lambda: EmbTerminal.run_command(EmbTerminal(), "ls"))
def retranslateUi(self, Dialog):
_translate = QtCore.QCoreApplication.translate
Dialog.setWindowTitle(_translate("Dialog", "Dialog"))
self.tabWidget.setTabText(self.tabWidget.indexOf(self.tab), _translate("Dialog", "Tab 1"))
self.tabWidget.setTabText(self.tabWidget.indexOf(self.tab_2), _translate("Dialog", "Tab 2"))
self.pushButton.setText(_translate("Dialog", "ls"))
from terminal5 import EmbTerminal
if __name__ == "__main__":
import sys
app = QtWidgets.QApplication(sys.argv)
Dialog = QtWidgets.QDialog()
ui = Ui_Dialog()
ui.setupUi(Dialog)
Dialog.show()
sys.exit(app.exec_())
您应该考虑以下几点:
- 您不应修改 Qt Designer 生成的代码(除非您了解其逻辑)
- 不要实现Qt Designer 生成的class 中的逻辑,建议创建一个新的class 继承自适当的widget 并使用另一个class 来填写它。
在你的情况下,问题是 lambda: EmbTerminal.run_command(EmbTerminal(), "ls")
中的 EmbTerminal() 对象仅在 lambda 为 运行 时存在,但 lambda 运行时间很短导致命令不发送导致错误。
综合以上,解决方案是:
from PyQt5 import QtCore, QtGui, QtWidgets
class Ui_Dialog(object):
def setupUi(self, Dialog):
Dialog.setObjectName("Dialog")
Dialog.resize(745, 496)
self.tabWidget = QtWidgets.QTabWidget(Dialog)
self.tabWidget.setGeometry(QtCore.QRect(100, 190, 561, 261))
self.tabWidget.setObjectName("tabWidget")
self.pushButton = QtWidgets.QPushButton(Dialog)
self.pushButton.setGeometry(QtCore.QRect(280, 70, 211, 71))
self.pushButton.setObjectName("pushButton")
self.retranslateUi(Dialog)
QtCore.QMetaObject.connectSlotsByName(Dialog)
def retranslateUi(self, Dialog):
_translate = QtCore.QCoreApplication.translate
Dialog.setWindowTitle(_translate("Dialog", "Dialog"))
self.pushButton.setText(_translate("Dialog", "ls"))
from terminal5 import EmbTerminal
class Dialog(QtWidgets.QDialog, Ui_Dialog):
def __init__(self, parent=None):
super().__init__(parent)
self.setupUi(self)
self.terminal = EmbTerminal()
self.tabWidget.addTab(self.terminal, "Terminal")
self.pushButton.clicked.connect(self.on_clicked)
@QtCore.pyqtSlot()
def on_clicked(self):
self.terminal.run_command("ls")
if __name__ == "__main__":
import sys
app = QtWidgets.QApplication(sys.argv)
w = Dialog()
w.show()
sys.exit(app.exec_())
另一方面,如果您只打算发送命令,则没有必要存储 QProcess,而是使用 QProcess: startDetached 并制作 run_command
一个 class 方法:
class EmbTerminal(QtWidgets.QWidget):
# ...
@staticmethod
def run_command(command = "ls" ):
program = "tmux"
options = []
options.extend(["send-keys"])
options.extend([command])
options.extend(["Enter"])
QtCore.QProcess.startDetached(program, options)
我正在尝试创建一个应用程序,它可以在单击按钮时执行嵌入式终端命令。实际问题发生在我单击按钮但没有任何反应时。 我有两个脚本,一个有终端小部件,另一个有主 GUI。任何帮助,将不胜感激。
这是第一个脚本
import sys
from PyQt5 import QtCore, QtWidgets
class EmbTerminal(QtWidgets.QWidget):
def __init__(self, parent=None):
super(EmbTerminal, self).__init__(parent)
self._process = []
self.start_process('urxvt',['-embed', str(int(self.winId())),"-e","tmux"])
def start_process(self,prog,options):
child = QtCore.QProcess(self)
self._process.append(child)
child.start(prog,options)
def run_command(self, command = "ls" ):
program = "tmux"
options = []
options.extend(["send-keys"])
options.extend([command])
options.extend(["Enter"])
self.start_process(program, options)
这是第二个剧本
from PyQt5 import QtCore, QtGui, QtWidgets
class Ui_Dialog(object):
def setupUi(self, Dialog):
Dialog.setObjectName("Dialog")
Dialog.resize(745, 496)
self.tabWidget = QtWidgets.QTabWidget(Dialog)
self.tabWidget.setGeometry(QtCore.QRect(100, 190, 561, 261))
self.tabWidget.setObjectName("tabWidget")
self.tab = QtWidgets.QWidget()
self.tab.setObjectName("tab")
self.tabWidget.addTab(EmbTerminal(), "Terminal")
self.tab_2 = QtWidgets.QWidget()
self.tab_2.setObjectName("tab_2")
self.tabWidget.addTab(self.tab_2, "")
self.pushButton = QtWidgets.QPushButton(Dialog)
self.pushButton.setGeometry(QtCore.QRect(280, 70, 211, 71))
self.pushButton.setObjectName("pushButton")
self.retranslateUi(Dialog)
QtCore.QMetaObject.connectSlotsByName(Dialog)
self.pushButton.clicked.connect(lambda: EmbTerminal.run_command(EmbTerminal(), "ls"))
def retranslateUi(self, Dialog):
_translate = QtCore.QCoreApplication.translate
Dialog.setWindowTitle(_translate("Dialog", "Dialog"))
self.tabWidget.setTabText(self.tabWidget.indexOf(self.tab), _translate("Dialog", "Tab 1"))
self.tabWidget.setTabText(self.tabWidget.indexOf(self.tab_2), _translate("Dialog", "Tab 2"))
self.pushButton.setText(_translate("Dialog", "ls"))
from terminal5 import EmbTerminal
if __name__ == "__main__":
import sys
app = QtWidgets.QApplication(sys.argv)
Dialog = QtWidgets.QDialog()
ui = Ui_Dialog()
ui.setupUi(Dialog)
Dialog.show()
sys.exit(app.exec_())
您应该考虑以下几点:
- 您不应修改 Qt Designer 生成的代码(除非您了解其逻辑)
- 不要实现Qt Designer 生成的class 中的逻辑,建议创建一个新的class 继承自适当的widget 并使用另一个class 来填写它。
在你的情况下,问题是 lambda: EmbTerminal.run_command(EmbTerminal(), "ls")
中的 EmbTerminal() 对象仅在 lambda 为 运行 时存在,但 lambda 运行时间很短导致命令不发送导致错误。
综合以上,解决方案是:
from PyQt5 import QtCore, QtGui, QtWidgets
class Ui_Dialog(object):
def setupUi(self, Dialog):
Dialog.setObjectName("Dialog")
Dialog.resize(745, 496)
self.tabWidget = QtWidgets.QTabWidget(Dialog)
self.tabWidget.setGeometry(QtCore.QRect(100, 190, 561, 261))
self.tabWidget.setObjectName("tabWidget")
self.pushButton = QtWidgets.QPushButton(Dialog)
self.pushButton.setGeometry(QtCore.QRect(280, 70, 211, 71))
self.pushButton.setObjectName("pushButton")
self.retranslateUi(Dialog)
QtCore.QMetaObject.connectSlotsByName(Dialog)
def retranslateUi(self, Dialog):
_translate = QtCore.QCoreApplication.translate
Dialog.setWindowTitle(_translate("Dialog", "Dialog"))
self.pushButton.setText(_translate("Dialog", "ls"))
from terminal5 import EmbTerminal
class Dialog(QtWidgets.QDialog, Ui_Dialog):
def __init__(self, parent=None):
super().__init__(parent)
self.setupUi(self)
self.terminal = EmbTerminal()
self.tabWidget.addTab(self.terminal, "Terminal")
self.pushButton.clicked.connect(self.on_clicked)
@QtCore.pyqtSlot()
def on_clicked(self):
self.terminal.run_command("ls")
if __name__ == "__main__":
import sys
app = QtWidgets.QApplication(sys.argv)
w = Dialog()
w.show()
sys.exit(app.exec_())
另一方面,如果您只打算发送命令,则没有必要存储 QProcess,而是使用 QProcess: startDetached 并制作 run_command
一个 class 方法:
class EmbTerminal(QtWidgets.QWidget):
# ...
@staticmethod
def run_command(command = "ls" ):
program = "tmux"
options = []
options.extend(["send-keys"])
options.extend([command])
options.extend(["Enter"])
QtCore.QProcess.startDetached(program, options)