使用正则表达式捕获 Python 脚本中的所有字符串

Question

这个问题的灵感来自于我尝试改编这个答案后失败的尝试：RegEx: Grabbing values between quotation marks

考虑以下 Python 脚本 (t.py)：

print("This is also an NL test")
variable = "!\n"
print('And this has an escaped quote "don\'t"  in it ', variable,
      "This has a single quote ' but doesn\'t end the quote as it" + \
      " started with double quotes")
if "Foo Bar" != '''Another Value''':
    """
    This is just nonsense
    """
    aux = '?'
    print("Did I \"failed\"?", f"{aux}")

我想捕获其中的所有字符串，如：

This is also an NL test
!\n
And this has an escaped quote "don\'t" in it
This has a single quote ' but doesn\'t end the quote as it
started with double quotes
Foo Bar
Another Value
This is just nonsense
?
Did I \"failed\"?
{aux}

我使用 re 模块编写了另一个 Python 脚本，从我对正则表达式的尝试中，找到大部分脚本的脚本是：

import re
pattern = re.compile(r"""(?<=(["']\b))(?:(?=(\?)).)*?(?=)""")
with open('t.py', 'r') as f:
    msg = f.read()
x = pattern.finditer(msg, re.DOTALL)
for i, s in enumerate(x):
    print(f'[{i}]',s.group(0))

结果如下：

[0] And this has an escaped quote "don\'t" in it
[1] This has a single quote ' but doesn\'t end the quote as it started with double quotes
[2] Foo Bar
[3] Another Value
[4] Did I \"failed\"?

为了改善我的失败，我也无法完全复制我在 regex101.com:

中找到的东西

顺便说一下，我正在使用 Python 3.6.9，我要求对正则表达式有更多的了解以破解这个。

Answer 1

因为你想匹配 ''' 或 """ 或 ' 或 " 作为分隔符，所以将所有这些都放在第一组中：

('''|"""|["'])

不要在它后面加上 \b，因为如果字符串以非单词字符开头，它就不会匹配这些字符串。

因为您想确保在引擎开始下一次迭代时 final 定界符不被视为起始定界符，所以您需要完全匹配它 (不仅仅是向前看）。

匹配除定界符以外的任何内容的中间部分可以是：

((?:\.|.)*?)

全部放在一起：

('''|"""|["'])((?:\.|.)*?)

你想要的结果将在第二个捕获组中：

pattern = re.compile(r"""(?s)('''|\"""|["'])((?:\.|.)*?)""")
with open('t.py', 'r') as f:
    msg = f.read()
x = pattern.finditer(msg)
for i, s in enumerate(x):
    print(f'[{i}]',s.group(2))

https://regex101.com/r/dvw0Bc/1

使用正则表达式捕获 Python 脚本中的所有字符串

Capture ALL strings within a Python script with regex

python

regex

string

double-quotes

single-quotes