无法使用传入 AWS SSM 命令的 awk 过滤器打印第二个字段

Question

我正在尝试从 AWS SSM 参数存储中获取详细信息。我存储了数据，SSM 参数存储中的值是这样的：

CompanyName\credits

请找到通过AWS CLI执行的SSM命令，输出结果如下：

aws ssm get-parameters --names "/Data/Details"

 - Output

{
    "Parameters": [
        {
            "Name": "/Data/Details",
            "Type": "String",
            "Value": "CompanyName\Credits",
            "Version": 1,
            "LastModifiedDate": "2019-08-13T18:16:40.836000+00:00",
            "ARN": "arn:aws:ssm:us-west-1:8484848448444:parameter/Data/Details"
        }
    ],
    "InvalidParameters": []
}  ```


In the above output, I am trying to print only **Credits** in **"Value": "CompanyName\Credits"**, so I have added more filters to my command as follows:

``` aws ssm get-parameters --names "/Data/Details" |grep -i "Value" |sed -e 's/[",]//g' |awk -F'\' '{print }' ```


The above command gives nothing in the output. But when I am trying to print the first field I am able  to see the output as  ** Value: CompanyName ** using the following command:

``` aws ssm get-parameters --names "/Data/Details" |grep -i "Value" |sed -e 's/[",]//g' |awk -F'\' '{print }' ```


Since this is Linux machine, the double slash in the field **Value : CompanyName\Credits ** occurred to escape the '\' character for the actual value CompanyName\Credits. Can someone let me know how can I modify the command to print only the value **Credits** in my output.

Regards,
Karthik

Answer 1

我认为这应该可行：

param_info=$(aws ssm get-parameters \
    --names "/Data/Details" \
    --query 'Parameters[0].Value' \
    --output text)

echo ${param_info} | awk -F'\' {'print '}

# or without awk

echo ${param_info#*\\}  # for Credit
echo ${param_info%\\*}  # for CompanyName

这个用query and output parameters to control output from the aws cli. Also bash parameter expansions都用了

无法使用传入 AWS SSM 命令的 awk 过滤器打印第二个字段

Unable to print the second field using awk filter passing in an AWS SSM Command

shell

amazon-web-services

aws-cli

ssm