Actionscript 2.0 (adobe flash cs6) 上基于平铺的运动

Question

所以我遇到了这个问题，我不知道如何为动作脚本 2.0 编写基于磁贴的 4 个方向 (NSWE) 移动代码。

我有这段代码，但它是动态运动，它使 char 在所有 8 个方向（NW、NE、SW、SE N、S、W、E）上移动。目标是将移动限制为基于图块且仅在 4 个方向上 (NSEW)

 onClipEvent(enterFrame)
{
    speed=5;
    if(Key.isDown(Key.RIGHT))
    {
        this.gotoAndStop(4);
        this._x+=speed;
    }
    if(Key.isDown(Key.LEFT))
    {
        this.gotoAndStop(3);
        this._x-=speed;
    }
    if(Key.isDown(Key.UP))
    {
        this.gotoAndStop(1);
        this._y-=speed;
    }
    if(Key.isDown(Key.DOWN))
    {
        this.gotoAndStop(2);
        this._y+=speed;
    }
}

Answer 1

最简单直接的方法是沿着 X 轴 OR 沿着 Y-轴，一次只有一个，不能同时有两个。

onClipEvent(enterFrame)
{
    speed = 5;

    dx = 0;
    dy = 0;

    // Figure out the complete picture of keyboard input.

    if (Key.isDown(Key.RIGHT))
    {
        dx += speed;
    }

    if (Key.isDown(Key.LEFT))
    {
        dx -= speed;
    }

    if (Key.isDown(Key.UP))
    {
        dy -= speed;
    }

    if (Key.isDown(Key.DOWN))
    {
        dy += speed;
    }

    if (dx != 0)
    {
        // Move along X-axis if LEFT or RIGHT pressed.
        // Ignore if it is none or both of them.

        this._x += dx;

        if (dx > 0)
        {
            this.gotoAndStop(4);
        }
        else
        {
            this.gotoAndStop(3);
        }
    }
    else if (dy != 0)
    {
        // Ignore if X-axis motion is already applied.
        // Move along Y-axis if UP or DOWN pressed.
        // Ignore if it is none or both of them.

        this._y += dy;

        if (dy > 0)
        {
            this.gotoAndStop(2);
        }
        else
        {
            this.gotoAndStop(1);
        }
    }
}

Actionscript 2.0 (adobe flash cs6) 上基于平铺的运动

Tile based movement on Actionscript 2.0 (adobe flash cs6)

actionscript-2

game-development

flash-cs6