将 JSON 传递给 Firebase Dynamic Link
Pass JSON to Firebase Dynamic Link
我希望我的用户在单击 Firebase Dynamic Link (FDL) 时导航到我的网页(起始页),并且我的应用程序用户转到特定页面(这里我需要额外的数据作为 JSON).
这是我的代码:
val dynamicLink = FirebaseDynamicLinks.getInstance().createDynamicLink()
.setLink(Uri.parse("{products:...some custom JSON}"))
.setDomainUriPrefix("https://mydomain.page.link")
.setAndroidParameters(DynamicLink.AndroidParameters.Builder().build()) //if set, a click on dynamic link will open android app
.setIosParameters(DynamicLink.IosParameters.Builder("com.foodhatapp.foodhatios").build())
.setSocialMetaTagParameters(DynamicLink.SocialMetaTagParameters.Builder()
.setTitle("Bismillah, FOODHHAAAT")
.setDescription("please click and order at foodhat!")
.setImageUrl(Uri.parse("http://h2866694.stratoserver.net/foodhat/images/products/62-1733-1f644aa6-30af-4237-9478-68a114d7600f.png"))
.build())
.buildShortDynamicLink()
.addOnSuccessListener {
i("teeeeest", it.shortLink.toString())
}
.addOnFailureListener {
i("teeeeest", "error at creating dynamic link...show popup to user..." +
"maybe his internet is broken etc... please check your internet connection and try again later")
}
如您所见,我正在尝试在 setLink()-Section 中传递 JSON...但是我在哪里可以正确传递 JSON?
我收到一个 FailureException
我知道 setLink() 需要格式正确的 URI...但是我想将 JSON 传递给我的应用程序,对于 web,只需导航到起始页,这样根 URL 的网页...
如何实现?
您可以像这样将 json 数据附加到 link 本身...
String json = "{}";//convert your json into string
String link = "http://yourdomainlink.com/?jsondata=" + json;
设置link
.setLink(Uri.parse(link));
然后像这样检索json(代码在java)
FirebaseDynamicLinks.getInstance()
.getDynamicLink(getIntent())
.addOnSuccessListener(this, new OnSuccessListener<PendingDynamicLinkData>() {
@Override
public void onSuccess(PendingDynamicLinkData pendingDynamicLinkData) {
// Get deep link from result (may be null if no link is found)
Uri deepLink = null;
if (pendingDynamicLinkData != null) {
deepLink = pendingDynamicLinkData.getLink();
String json = deepLink.getQueryParameter("jsondata");
}
}
});
希望对您有所帮助
我希望我的用户在单击 Firebase Dynamic Link (FDL) 时导航到我的网页(起始页),并且我的应用程序用户转到特定页面(这里我需要额外的数据作为 JSON).
这是我的代码:
val dynamicLink = FirebaseDynamicLinks.getInstance().createDynamicLink()
.setLink(Uri.parse("{products:...some custom JSON}"))
.setDomainUriPrefix("https://mydomain.page.link")
.setAndroidParameters(DynamicLink.AndroidParameters.Builder().build()) //if set, a click on dynamic link will open android app
.setIosParameters(DynamicLink.IosParameters.Builder("com.foodhatapp.foodhatios").build())
.setSocialMetaTagParameters(DynamicLink.SocialMetaTagParameters.Builder()
.setTitle("Bismillah, FOODHHAAAT")
.setDescription("please click and order at foodhat!")
.setImageUrl(Uri.parse("http://h2866694.stratoserver.net/foodhat/images/products/62-1733-1f644aa6-30af-4237-9478-68a114d7600f.png"))
.build())
.buildShortDynamicLink()
.addOnSuccessListener {
i("teeeeest", it.shortLink.toString())
}
.addOnFailureListener {
i("teeeeest", "error at creating dynamic link...show popup to user..." +
"maybe his internet is broken etc... please check your internet connection and try again later")
}
如您所见,我正在尝试在 setLink()-Section 中传递 JSON...但是我在哪里可以正确传递 JSON?
我收到一个 FailureException
我知道 setLink() 需要格式正确的 URI...但是我想将 JSON 传递给我的应用程序,对于 web,只需导航到起始页,这样根 URL 的网页...
如何实现?
您可以像这样将 json 数据附加到 link 本身...
String json = "{}";//convert your json into string
String link = "http://yourdomainlink.com/?jsondata=" + json;
设置link
.setLink(Uri.parse(link));
然后像这样检索json(代码在java)
FirebaseDynamicLinks.getInstance()
.getDynamicLink(getIntent())
.addOnSuccessListener(this, new OnSuccessListener<PendingDynamicLinkData>() {
@Override
public void onSuccess(PendingDynamicLinkData pendingDynamicLinkData) {
// Get deep link from result (may be null if no link is found)
Uri deepLink = null;
if (pendingDynamicLinkData != null) {
deepLink = pendingDynamicLinkData.getLink();
String json = deepLink.getQueryParameter("jsondata");
}
}
});
希望对您有所帮助