无法使用 Crispy Forms 通过外键上传数据

Cannot upload data through a foreign keys with Crispy Forms

我显示类别和子类别的值,从那里获取值并将其保存为新闻实体中的外键。

models.py

class News(models.Model):    
    name = models.CharField(max_length=50)
    pic = models.ImageField()
    catid = models.ForeignKey(SubCat, on_delete = models.DO_NOTHING)

class Cat(models.Model): 
    name = models.CharField(max_length=50)

class SubCat(models.Model):   
    name = models.CharField(max_length=50)
    catid = models.ForeignKey(Cat, on_delete = models.CASCADE)

add_news.html

  <label class="col-md-1 control-label" for="example-text-input">Text Input</label>
  <div class="col-md-5">
       <input id="newstitle" name="newstitle" type="text" class="form-control" placeholder=".col-md-7">
  </div>

  <select id="newscat" name="newscat" class="select-chosen" data-placeholder="Choose a Category.." style="width: 250px;">
     {% for i in subcat %}
         <option value="{{ i.pk }}">{{ i.catid.name }} | {{ i.name }}</option>
     {% endfor %}
  </select>

image 然后我使用查询获取了所有值并像这样保存它们:

views.py

@login_required(login_url='mylogin')
def news_add(request):
    subCat = SubCat.objects.all()
     catID = request.POST['newscat']
     if request.method == 'POST':
             newstitle = request.POST['newstitle']                      
             newCatID = SubCat.objects.get(pk=catID)
             pic= request.FILES['picture']
             news = News(name=newstitle, catid=newCatID, pic=pic)
             ...
             news.save()
      else:
          return render(request, 'back/news_add.html', {'subcat' : subCat})

但是,现在我如何使用 crispy 表单 来显示带有子类别的相同类别列表并将其保存在我的模型中PK(猫)?

所以,我只能显示这个

add_news.html

<div class="col-md-5">
       {{ form.name|as_crispy_field }}
</div>
<div class="col-md-5">
       {{ form.pic|as_crispy_field }}
</div>
<div class="col-md-5">
       {{ form.catid.name|as_crispy_field }} {{ form.name|as_crispy_field }} # Not possible
</div>

forms.py

class NewsForm(ModelForm):
    class Meta:
        model = News
        fields = ['name', 'pic', 'catid',]       
        labels = {'name': _('Title'),                  
                    'catid': _(''),
                    'pic': _('picture'),
                    }

views.py

@login_required(login_url='mylogin')
def news_add(request):
    subCat = SubCat.objects.all()
    if request.method == 'POST':

        form = NewsForm(request.POST, request.FILES)

        if form.is_valid():

            new = form.save()
            new.save()
            #form.save_m2m()

            return redirect('news_list')

    else:
        form = NewsForm()
        #newCatID = get_object_or_404(SubCat, pk = catID)

    return render(request, 'back/news_add.html', {'form':form, 'subcat' : subCat})

我把我的问题描述的尽量详细了,因为我已经想了好几天了

也许始终将 SubCat 与 Cat 一起显示是有意义的:

class SubCat(models.Model):   
    name = models.CharField(max_length=50)
    catid = models.ForeignKey(Cat, on_delete = models.CASCADE)

    def __str__(self):
        return "{} | {}".format(self.catid.name, self.name)