如何从 webview 中的长按链接获取 URL？

Question

我想在 android 中为 Web 视图创建上下文菜单。我的问题是我无法从单击的 link 中获取 URL。我写这段代码是为了记录点击的 link:

webView.setOnLongClickListener(new View.OnLongClickListener() {
        @Override
        public boolean onLongClick(final View v) {

            WebView webView1 = (WebView) v;
            WebView.HitTestResult hitTestResult = webView1.getHitTestResult();
            Log.i("LinkClicked", hitTestResult.getExtra());

            return false;
        }
    });

使用此代码，当在 Whosebug 等网站中长按 links 时，记录如下：

https://whosebug.com/questions

一切正常，但是当长按google搜索结果时，日志如下：

data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAABAAAAAQCAMAAAAoLQ9TAAAAJFBMVEVHcEz/AAD/AAD/AAD/AAD/AAD/AAD/AAD/g4P/////KCj/7e0I8rGvAAAAB3RSTlMAT0g5Ggp+EilkVQAAAENJREFUGJVjYCAGsDAzggEzC5jLxo4E2BgYWNlRACsDM5jmggkwMzCBaQ5uqBATTICTk4OAAEILhqEY1mI4DNPphAAASIsES4gsgWgAAAAASUVORK5CYII=

它不 return 一个 link。我该如何解决这个问题？

Answer 1

public class MainActivity extends AppCompatActivity {

    WebView webView;
    String URL1 = "";

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        webView = findViewById(R.id.webview);

        webView.clearHistory();
        webView.getSettings().setJavaScriptEnabled(true);
        webView.getSettings().setLoadWithOverviewMode(true);
        webView.getSettings().setUseWideViewPort(true);
        webView.setWebViewClient(new WebViewClient() {

            public void onReceivedError(WebView view, int errorCode, String description, String failingUrl) {

            }

            public void onPageFinished(WebView view, String url) {

            }

            @Override
            public boolean shouldOverrideUrlLoading(WebView view, String url) {
                URL1 = url;
                return super.shouldOverrideUrlLoading(view, url);
            }
        });
        webView.loadUrl(URL1);
        // Register the context menu for web view
        registerForContextMenu(webView);
    }

    @Override
    public void onCreateContextMenu(ContextMenu menu, View v, ContextMenu.ContextMenuInfo menuInfo) {
        super.onCreateContextMenu(menu, v, menuInfo);

        // Get the web view hit test result
        final WebView.HitTestResult result = webView.getHitTestResult();

        // If user long press on url
        if (result.getType() == WebView.HitTestResult.ANCHOR_TYPE ||
                result.getType() == WebView.HitTestResult.SRC_ANCHOR_TYPE) {

            // Set the title for context menu
            menu.setHeaderTitle("\t\t\t\t\t\t\t\t\t\t ◦ ◉ ⦿ Select ⦿ ◉ ◦ \t");

            // Add an item to the menu
            menu.add(0, 1, 0, " \t \t➤\t Show URL")
                    .setOnMenuItemClickListener(new MenuItem.OnMenuItemClickListener() {
                        @Override
                        public boolean onMenuItemClick(MenuItem menuItem) {
                            String Pressed_url = result.getExtra();
                            Toast.makeText(MainActivity.this, "URL is:-" + Pressed_url,
                                    Toast.LENGTH_SHORT).show();
                            return false;
                        }
                    });
        }
    }
}

Download Full Code from github.

Output

如何从 webview 中的长按链接获取 URL？

How to get URL from long click links in a webview?

android

url

android-webview

long-click