当数组为 null 或为空时如何抛出 IllegalArgumentException？

Question

    /**
     * This constructor accepts an array of points as input. Copy the points into the array points[]. 
     * 
     * @param  pts  input array of points 
     * @throws IllegalArgumentException if pts == null or pts.length == 0.
     */
    protected AbstractSorter(Point[] pts) throws IllegalArgumentException
    {
        try{
            for(int i = 0; i < pts.length; i++)
            {
                points[i] = pts[i];
            }
        }
        catch()
        {

        }
    }

我知道这应该很简单，但是在这些情况下我该如何抛出这个异常？

Answer 1

protected AbstractSorter(Point[] pts) throws IllegalArgumentException
{
        if(pts == null || pts.length ==0 )
          throw new IllegalArgumentException();
        for(int i = 0; i < pts.length; i++)
        {
            points[i] = pts[i];
        }
}

Answer 2

/**
     * This constructor accepts an array of points as input. Copy the points into the array points[]. 
     * 
     * @param  pts  input array of points 
     * @throws IllegalArgumentException if pts == null or pts.length == 0.
     */
    protected AbstractSorter(Point[] pts) throws IllegalArgumentException
    {
        if(pts == null || pts.length == 0)
            throw new IllegalArgumentException();
        else{
            for(int i = 0; i < pts.length; i++)
                points[i] = pts[i];
        }
    }

这是我根据您的建议得出的。

Answer 3

你的代码应该是这样的，

protected AbstractSorter(Point[] pts) throws IllegalArgumentException
{
    if(pts == null || pts.length == 0 ){
      throw new IllegalArgumentException();
    }
    for(int i = 0; i < pts.length; i++)
    {
        points[i] = pts[i];
    }
}

当数组为 null 或为空时如何抛出 IllegalArgumentException？

How to throw an IllegalArgumentException when an array is null or empty?

java

throws