return 评估 javascript 函数到终端

Question

我正在尝试 return 一个已经计算到终端的函数。我尝试使用 window.onload()、console.log(); alert(); 但 URL 未被评估并发送到终端。

I 运行下面的代码使用命令 phantomjs test.js

var webPage = require('webpage');
var page = webPage.create();

function testlink() {
  return(["h","t","t","p","s",":","\/","\/","i","b","m",".","c","o","m"]);
}

window.onload = testlink;
console.log(testlink);
alert(testlink);

而不是得到（这就是我想要的）

https://ibm.com

我明白了

function testlink() {
  return(["h","t","t","p","s",":","\/","\/","i","b","m",".","c","o","m"]);
}

Ps：我正在使用 Ubuntu 18.04 和 phantomjs 2.1.1

Answer 1

尝试 console.log(testlink()) 而不是 console.log(testlink)

如果我们想连接该数组中的所有字符，只需 return:

["h","t","t","p","s",":","\/","\/","i","b","m",".","c","o","m"].join("")

或者如果您不想更改函数，请执行 console.log(testlink().join(""))

return 评估 javascript 函数到终端

return evaluated javascript function to terminal

javascript

phantomjs