错误 [E0308]：不匹配的类型 — 应为 `&str`，找到结构 `std::string::String`

Question

我正在制作一款井字游戏。代码不完整，但我被困在这里。我想打印 array_display 到控制台，但是当我分配字符串时，弹出错误。

use std::io;

fn main() {
    let mut player1: String = String::new();
    let mut player2: String = String::new();
    let mut positions = ["1", "2", "3", "4", "5", "6", "7", "8", "9"];

    let mut lets_play = true;

    println!("Welcome to tic tac toe");
    println!("Player 1 please select what symbol you want to be : (x or o)");
    io::stdin().read_line(&mut player1);

    player1 = player1.to_lowercase();
    println!("{:?}", player1);

    if player1.trim() == "x" {
        player1 = String::from("x");
        player2 = String::from("o");
        println!("Player 1 is x");
    } else if player1.trim() == "o" {
        player1 = String::from("o");
        player2 = String::from("x");
        println!("Player 1 is o");
    } else {
        println!("Input is not valid");
        lets_play = false;
    }
    if lets_play {
        println!("Let's start the game :");

        print_board(&mut positions);
    } else {
        println!("Please reset the game");
    }
}

fn print_board(arr: &mut [&str]) {
    let mut counter = 0;
    let mut array_display = ["1", "2", "3"];
    let mut array_position = 0;
    let mut string_for_array = String::new();

    for i in 0..arr.len() {
        string_for_array.push_str(arr[i]);
        counter += 1;
        if counter == 3 {
            println!(
                "array_display[{}] value =  {}",
                array_position, string_for_array
            );
            array_display[array_position] = string_for_array.to_string();
            println!("String to push {:?}", string_for_array);
            string_for_array = String::from("");
            println!("Array position {}", array_position);
            array_position += 1;
            counter = 0;
        }
    }
}

错误：

error[E0308]: mismatched types
  --> src/main.rs:52:45
   |
52 |             array_display[array_position] = string_for_array.to_string();
   |                                             ^^^^^^^^^^^^^^^^^^^^^^^^^^^^
   |                                             |
   |                                             expected `&str`, found struct `std::string::String`
   |                                             help: consider borrowing here: `&string_for_array.to_string()`

Answer 1

您的代码中当前的问题是 string_for_array.to_string() 创建了一个新的 String，但 array_display 数组包含 &str 个引用。

编译器在这里给出的建议（替换为 &string_for_array.to_string()）不起作用，因为 .to_string() 的结果将在该行的末尾被释放，并且您将有一个无效的 &str参考。

因此，问题是：某些变量需要拥有该字符串。由于string_for_array是后面修改的，所以不能用。自然的选择是 array_display （因为那是该字符串无论如何都会存在的地方）。因此，首先修改此数组以包含拥有的 Strings 而不是 &str 引用：

    let mut array_display = ["1".to_owned(), "2".to_owned(), "3".to_owned()];

然后其余代码将编译。

错误 [E0308]：不匹配的类型 — 应为 `&str`，找到结构 `std::string::String`

error[E0308]: mismatched types — expected `&str`, found struct `std::string::String`

rust

type-mismatch