C/C libcurl如何POST表单提交，只是普通的web表单提交数据

Question

我想模拟web表单提交到PHPAPI，但是失败了，我试了很多方法。我的代码

#define HADES "Content-Type:application/x-www-form-urlencoded;charset=utf-8"

int SendPacket(char *packet, const char *server)
{
    curl_global_init(CURL_GLOBAL_ALL);
    CURL *curl = curl_easy_init();
    if (!curl) {
        return -1;
    }
    CURLcode ret;
    struct curl_slist *haderlist = NULL;
    struct curl_httppost *post = NULL;
    struct curl_httppost *last = NULL;
    haderlist = curl_slist_append(haderlist, HADES);

    curl_formadd(&post, &last, CURLFORM_COPYNAME, "username",
             CURLFORM_COPYCONTENTS,
             "11111111111", CURLFORM_END);
    curl_formadd(&post, &last, CURLFORM_COPYNAME, "password",
             CURLFORM_COPYCONTENTS,
             "111111", CURLFORM_END);
    curl_formadd(&post, &last, CURLFORM_COPYNAME, "client", CURLFORM_FILE,
             "wap", CURLFORM_END);


    curl_easy_setopt(curl, CURLOPT_HTTPHEADER, haderlist);
    curl_easy_setopt(curl, CURLOPT_URL, server);
    curl_easy_setopt(curl, CURLOPT_POST, 1);
    curl_easy_setopt(curl, CURLOPT_POSTFIELDS, post); 
    curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, write_callback);

    //SendData
    ret = curl_easy_perform(curl);
    if (ret != CURLE_OK ) {
        curl_easy_strerror(ret);

        return -1;
    }
    return 0;
}

我把post的参数改成这个格式可以正常发送了这样：username=11111&password=1111&client=wap 而不是使用form_add函数，但是我不知道该怎么做。如何纠正这个问题？我不知道

Answer 1

您正在混合使用表单编码。 CURLOPT_POSTFIELDS 期望 URL-encoded 形式（例如 username = 11111&password =1111&client=wap），而 curl_formadd 生成 multipart/form-data 编码形式。将 CURLOPT_HTTPPOST 与 curl_formadd 一起使用，或者在 url-encoded 表格上使用 CURLOPT_POSTFIELDS。

无论哪种情况，您都不需要添加 Content-Type header，因为它会自动添加。

Answer 2

 tried to use mime to successfully solve the code as follows

int SendPacket(char *packet, const char *server)
{
    curl_global_init(CURL_GLOBAL_ALL);
    CURL *curl = curl_easy_init();
    if (!curl) {
        return -1;
    }
    CURLcode ret;

    curl_mime *mime;
    curl_mimepart *part1;
    curl_mimepart *part2;
    curl_mimepart *part3;

    mime = curl_mime_init(curl);
    part1 = curl_mime_addpart(mime);
    part2 = curl_mime_addpart(mime);
    part3 = curl_mime_addpart(mime);

    //Add part to the mime handle, each of which is a pair of key(name)value(data)
    curl_mime_data(part1, "111111", CURL_ZERO_TERMINATED);
    curl_mime_name(part1,"username");
    curl_mime_data(part2, "111111", CURL_ZERO_TERMINATED);
    curl_mime_name(part2, "password");
    curl_mime_data(part3, "wap", CURL_ZERO_TERMINATED);
    curl_mime_name(part3, "client");

    curl_easy_setopt(curl, CURLOPT_MIMEPOST, mime);
    curl_easy_setopt(curl, CURLOPT_URL, server);    
    curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, write_callback);
    curl_easy_setopt(curl, CURLOPT_WRITEDATA, NULL);

    ret = curl_easy_perform(curl);
    if (ret != CURLE_OK ) {
        curl_easy_strerror(ret);

        return -1;
    }
    return 0;
}

Above is mock to simulate web form submission

C/C libcurl如何POST表单提交，只是普通的web表单提交数据

C / C libcurl how to POST form submission, just ordinary web form submission data

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