如何获取值 Angular 单元测试 CSSStyleDeclaration

How to get value Angular unit test CSSStyleDeclaration

我试试测试Angular材质mat-expansion-panel open.

因此,我使用以下代码进行测试。

describe('Selected first expansion panel', () => {
    beforeEach(() => {
        const header = fixture.debugElement.query(By.css('#panel1 .mat-expansion-panel-header'))!.nativeElement;
        header.click();
        fixture.detectChanges();
    });
    it('should show first expansion panel content', () => {
        const first = fixture.debugElement.query(By.css('#panel1 .mat-expansion-panel-content'))!.nativeElement;
        console.log(first.style);
        expect(first.style.visibility).toEqual('visible');
    });
});

低于控制台(console.log(first.style))输出在"it"

CSSStyleDeclaration {alignContent: "", alignItems: "", alignSelf: "", alignmentBaseline: "", all: "", …}
cssText: "visibility: visible;"
length: 1
parentRule: null
cssFloat: ""
0: "visibility"
...
visibility: "visible"
...

但是,expect(first.style.visibility).toEqual('visible') 失败,Expected '' 等于 'visible'.

如何获得

尝试在 window 对象上使用 getComputedStyle

it('should show first expansion panel content', () => {
        const first = fixture.debugElement.query(By.css('#panel1 .mat-expansion-panel-content'))!.nativeElement;
        const styles = getComputedStyle(first);
        console.log(styles); // make sure you get an object
        expect(styles.visibility).toEqual('visible');
    });