使用 FlaskForm 进行错误检查和闪烁错误消息

Question

我有一个如下设置的表单，最终，我在调试模式下得到的错误是 sqlalchemy.exc.IntegrityError: (sqlite3.IntegrityError) UNIQUE constraint failed。我明白为什么，但我希望将此错误呈现给用户，以便他们了解问题所在。

class RegistrationForm(FlaskForm):
    company_url = StringField('Company Website', validators=[DataRequired(), URL(message='Must be a valid URL')])
    password = PasswordField(
        'Password', validators=[DataRequired(), EqualTo('pass_confirm',
                                                        message='Passwords must match')]
    )
    pass_confirm = PasswordField('Confirm Password', validators=[DataRequired()])
    submit = SubmitField('Register!')

但是，当在表单中输入并提交不正确的 URL 结构时，我无法让它在 html 页面中为用户闪现错误消息。 html 页面如下。我也会把 base.html 放在下面。

{% extends "base.html" %}
{% block content %}
    <form method="POST">
        {{form.hidden_tag()}}
        {{form.company_url.label}}{{form.company_url()}}<br>
        {{form.password.label}}{{form.password()}}<br>
        {{form.pass_confirm.label}}{{form.pass_confirm()}}<br>
        {{form.submit()}}
    </form>
{% endblock %}

<!DOCTYPE html>
<html>
  <head>
   ...some code here
  </head>
  <body>
    <!-- Just an image -->
<nav class="navbar navbar-dark bg-dark">
  <span class="align-bottom text-light">Creating connections, saving time</span>
</nav>

    {% with messages = get_flashed_messages() %} {% if messages %} {% for
    message in messages %}
    <div class="alert alert-warning alert-dismissible" role="alert">
      <button
        type="button"
        class="close"
        data-dismiss="alert"
        aria-label="Close"
      >
        <span aria-hidden="true">×</span>
      </button>
      {{message}}
    </div>
    {% endfor %} {% endif %} {% endwith %} {% block content %} {% endblock %}
  </body>
</html>

views.py是：

@app.route('/register', methods=['GET', 'POST'])
def register():

    form = RegistrationForm()

    if form.validate_on_submit():
        user = Buyers(
            company_url=form.company_url.data,
            password=form.password.data
        )

        db.session.add(user)
        db.session.commit()
        flash("Thank you for registering.")
        return redirect(url_for('login'))

    return render_template('register.html', form=form)

如何处理表单中的错误以确保用户知道他们输入的 URL 结构不正确？我处于调试模式，现在 register.html 页面基本上只是重新加载，没有任何关于原因的消息。谢谢！

Answer 1

views.py :

import validators

@app.route('/register', methods=['GET', 'POST'])
def register():

    form = RegistrationForm()

    if form.validate_on_submit():
        isUrlValid=validators.url(form.company_url.data)
        if isUrlValid==True:
            user = Buyers(
                company_url=form.company_url.data,
                password=form.password.data
            )
            db.session.add(user)
            db.session.commit()
            flash("Thank you for registering.")
            return redirect(url_for('login'))
        else:
            flash("URL is not valid. Please enter a valid URL")
            return redirect(url_for('register'))

    return render_template('register.html', form=form)

使用 FlaskForm 进行错误检查和闪烁错误消息

error checking and flashing error messages with FlaskForm

flask

python-3.x

flask-sqlalchemy

flask-wtforms